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Nataly_w [17]
3 years ago
7

7. Find the length of HP. 12 P 9 H

Mathematics
2 answers:
borishaifa [10]3 years ago
5 0

Answer and Step-by-step explanation:

To find the length of HP, we must use the Pythagorean Theorem.

This theorem helps us solve for the sides of any <em><u>right</u></em> triangle.

The equation for the Pythagorean Theorem is:

a^{2}+ b^{2} = c^{2}, in which a and b are the legs, while c is the hypotenuse.

Let's plug in our values into the equation to find the length of HP.

We will use the variable x to represent HP.

9^{2}+ 12^{2} = x^{2} \\\\\\Square.the.9.and.the.12.\\\\\\81 + 144 = x^2\\\\\\Add.\\\\\\225 = x^2\\\\\\Square.both.sides.\\\\\\\sqrt{225}  = \sqrt{x^2} \\\\\\15 = x = HP

<u>So, we get our answer to be 15.</u>

<u></u>

<u>The length of HP is 15.</u>

<u></u>

<u></u>

<u></u>

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

bearhunter [10]3 years ago
4 0

Step-by-step explanation:

hope it is helpful to you

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Since there is no decimal point, the answer is 345276.
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Find the next two numbers in a pattern?<br><br> 7, - 28,112, - 448 __, __, . . .
Igoryamba

Answer:

1,792    -7168

the pattern is to multiply by -4

Step-by-step explanation:

7 · -4 = -28

-28 · -4 = 112

112 · -4 = -448

-448 · -4 = 1,792

1,792 · -4 = -7168

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3 years ago
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Flura [38]
It is 5.6 I am almost positive
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maksim [4K]

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Attached as picture. Please read fully
Troyanec [42]

a. The velocity t = v = Ce_{n} (\frac{mo}{mo - kt} ) - gt

b. v60 = 7164

<h3>How to solve for the velocity</h3>

mdv/dt = ck - mg

dv/dt = ck/m - mg/m

= ck/m - g

dv = (\frac{ck}{Mo-Kt} -g)dv

Integrate the two sides of the equation to get

v -\frac{ck}{k} e_{n} (Mo- kt)-gt+c

v = Ce_{n} (\frac{mo}{mo - kt} ) - gt

b. fuel accounts for 55% of the mass

So final mass after fuel is burned out is = 0.45

c=2500

g=9.8

t=60

v = -2500ln0.45 - 9.8 x 60

= 7752 - 588

= 7164

<h3>Complete question</h3>

A rocket, fired from rest at time t = 0, has an initial mass of m0 (including its fuel). Assuming that the fuel is consumed at a constant rate k, the mass m of the rocket, while fuel is being burned, will be given by m0 - kt. It can be shown that if air resistance is neglected and the fuel gases are expelled at a constant speed c relative to the rocket, then the velocity of the rocket will satisfy the equation where g is the acceleration due to gravity.

dv dt m =ck - mg

(a) Find v(t) keeping in mind that the mass m is a function of t.

v(t) =

m/sec

(b) Suppose that the fuel accounts for 55% of the initial mass of the rocket and that all of the fuel is consumed at 60 s. Find the velocity of the rocket in meters per second at the instant the fuel is exhausted. [Note: Take g = 9.8 m/s² and c = 2500 m/s.]

v(60) =

m/sec [Round to nearest whole number]

Raed more on velocity here

brainly.com/question/25749514

#SPJ1

8 0
1 year ago
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