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laiz [17]
3 years ago
11

The approximate distance in miles between Los Angeles and a commercial jet flying from Boston to Los Angeles can be found using

the function m=-475t+2,650, where t is the number of hours the jet has been flying. Which number of hours and minutes is closest to the amount of time that the jet has been flying if the jet is 1,500 miles from Los Angeles?
A.) 2 hours and 25 minutes
B.) 8 hours and 44 minutes
C.) 3 hours and 16 minutes
D.) 9 hours and 13 minutes
Mathematics
2 answers:
ki77a [65]3 years ago
5 0
You're given the value of m so you plug that in the equation given to get 1500=-475t+2650. Now with some algebra just solve it for t! so subtract 2650 and get -1150=-475t. Now divide by -475 and get 2.4. Now the t value is already in hours, so there's no conversions, and the closest answer is A! This makes sense because it's an approximation :)
Anika [276]3 years ago
3 0

A.) 2 hours and 25 minutes

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Halp me :<<<<<<<<<<<<<<​
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Answer:

4^2+2^2, 5^2, 6^2-6

Step-by-step explanation:

4 to the power of 2 is 16 and 2 to the power of 2 is 4. 16+4 is 20.

5 to the power of 2 is 25 which is greater than 20.

6 to the power of 2 is 36 minus 6 is 30 which is greater than 25 and 20.

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Mark signed an appointment to receive internet service on his mobile phone for the service he pays a monthly fee plus a charge f
FinnZ [79.3K]

Answer:

<em>Mark used 6.43 megabytes of data.</em>

Step-by-step explanation:

The given equation is:   5.25+0.3m=7.18 , where m is amount of data used in megabyte.

For finding the amount of data Mark used, <u>we need to solve the above equation for m</u>.

First subtracting 5.25 from both sides, we will get.....

5.25+0.3m-5.25= 7.18-5.25\\ \\ 0.3m=1.93

Now, dividing both sides by 0.3 ...........

m=\frac{1.93}{0.3}=6.4333... \approx 6.43

<em>(Rounded to the nearest hundredth)</em>

Thus, Mark used 6.43 megabytes of data.

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