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laiz [17]
3 years ago
11

The approximate distance in miles between Los Angeles and a commercial jet flying from Boston to Los Angeles can be found using

the function m=-475t+2,650, where t is the number of hours the jet has been flying. Which number of hours and minutes is closest to the amount of time that the jet has been flying if the jet is 1,500 miles from Los Angeles?
A.) 2 hours and 25 minutes
B.) 8 hours and 44 minutes
C.) 3 hours and 16 minutes
D.) 9 hours and 13 minutes
Mathematics
2 answers:
ki77a [65]3 years ago
5 0
You're given the value of m so you plug that in the equation given to get 1500=-475t+2650. Now with some algebra just solve it for t! so subtract 2650 and get -1150=-475t. Now divide by -475 and get 2.4. Now the t value is already in hours, so there's no conversions, and the closest answer is A! This makes sense because it's an approximation :)
Anika [276]3 years ago
3 0

A.) 2 hours and 25 minutes

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The area of the given composite figure is 34 square feet

<h3>Area of rectangle</h3>

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Read 2 more answers
Identify the intervals on which each quadratic function is positive Part 1
Gemiola [76]

Answer:  1) (-∞, -6) U (-3, ∞)

               2) (-∞, -4) U (2, ∞)

               3) (-∞, -3) U (8, ∞)

<u>Step-by-step explanation:</u>

Find the zeros. Since the a-value is positive, the curve will be positive to the left of the leftmost zero and to the right of the rightmost zero.  +   -   +

                                                                                                     ←---|----|--→

1) y = x² + 9x + 18

  y = (x + 3)(x + 6)

 0 = (x + 3)(x + 6)

 0 = x + 3       0 = x + 6             +         --           +

 x = -3             x = -6              ←------|-----------|--------→

                                                     -6           -3

Positive Interval: (-∞, -6) U (-3, ∞)    

2) y = x² + 2x - 8

  y = (x + 4)(x - 2)

 0 = (x + 4)(x - 2)

 0 = x + 4       0 = x - 2              +         --          +

 x = -4             x = 2               ←------|-----------|--------→

                                                     -4            2

Positive Interval: (-∞, -4) U (2, ∞)    

3) y = x² - 5x - 24

  y = (x + 3)(x - 8)

 0 =  (x + 3)(x - 8)

 0 = x + 3       0 = x - 8               +        --           +

 x = -3             x = 8               ←------|-----------|--------→

                                                     -3            8

Positive Interval: (-∞, -3) U (8, ∞)    

   

4 0
3 years ago
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