<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
Answer:
i try my best to find the answer if i can give me some time when i will find then i will tell you
Step-by-step explanation:
Answer:
I need the length, width, and height
Step-by-step explanation:
Answer:
E
Step-by-step explanation:
Answer:
see explanation
Explanation:
the graph of g(x) is the graph of f(x) shifted vertically by
+ 6 units
or equivalent to a translation
(
0
6
)
in general
g
(
x
)
=
x
2
±
a
for
a
>
0
shift is
(
0
a
)
↑
⏐
⏐
⏐
⏐
for
a
<
0
shift is
(
0
−
a
)
⏐
⏐
⏐
⏐
↓
graph{(y-x^2)(y-x^2-6)=0 [-20, 20, -10, 10]}
Step-by-step explanation:
