Ask question

Ask question

All categories

2 years ago

5

If a mat costs 9800kr, what combination of two reductions in it's price, which have to add up to 100%, e.g: The price was first

reduced by 40% and then 60%, will yield the cheapest price for the mat?

1 answer:

Gre4nikov [31]2 years ago

7 0

Step-by-step explanation:

if a mat was 9800kr and the price was reduced by about 40% it would be 245 whereas another 60 would end up 980 itself so I'm not too sure as the cheapest alternative would be 40%

You might be interested in

Which of the following equations could be the result of using the comparison method to solve the system shown?

masya89 [10]

Answer:

6-2y=4y+8

since you show x through y

Answer:

The result that is obtained on comparing the system of equations in order to get the solution to the system of equations is:

6 -2y =4y + 8

Step-by-step explanation:

We are given a system of equations in term of variable x and y as follows:

x + 2y = 6 --------(1)

x - 4y = 8-------------(2)

From equation (1) we have the value of x in terms of y as:

x=6-2y

From equation (2) we have the value of x in terms of y as:

x=8+2y

Hence, on equation the above two values of 'x' we obtain:

6 - 2y = 4y + 8

ghope this helps

5 0

2 years ago

Read 2 more answers

Can someone help me with this pls i’ll give brainliest

Rom4ik [11]

Answer: C

Step-by-step explanation:

1 1/8 = 1.125

3/4 = .75

4 0

3 years ago

PLEASE HELP ME BUILD AN EQUATION WITH THIS

anyanavicka [17]

Answer:

12mph + bmph = 45 - 26.5c

Step-by-step explanation:

8 0

2 years ago

What is the quotient? URGENT!!

jeyben [28]

Answer:

The answer is A.

Step-by-step explanation:

You have to multiply by converting the second fraction into upside down :

$\frac{4x + 1}{6x} \div \frac{x}{3x - 1}$

$= \frac{4x + 1}{6x} \times \frac{3x - 1}{x}$

$= \frac{(4x + 1)(3x - 1)}{x(6x)}$

$= \frac{12 {x}^{2} - 4x + 3x - 1}{6 {x}^{2} }$

$= \frac{12 {x}^{2} - x - 1 }{6 {x}^{2} }$

5 0

2 years ago

Consider a sample with data values of 27, 24, 21, 16, 30, 33, 28, and 24. Compute the 20th, 25th, 65th, and 75th percentiles. 20

densk [106]

Answer:

$P_{20} = 20$ --- 20th percentile

$P_{25} = 21.75$ --- 25th percentile

$P_{65} = 27.85$ --- 65th percentile

$P_{75} = 29.5$ --- 75th percentile

Step-by-step explanation:

Given

27, 24, 21, 16, 30, 33, 28, and 24.

N = 8

First, arrange the data in ascending order:

Arranged data: 16, 21, 24, 24, 27, 28, 30, 33

Solving (a): The 20th percentile

This is calculated as:

$P_{20} = 20 * \frac{N +1}{100}$

$P_{20} = 20 * \frac{8 +1}{100}$

$P_{20} = 20 * \frac{9}{100}$

$P_{20} = \frac{20 * 9}{100}$

$P_{20} = \frac{180}{100}$

$P_{20} = 1.8th\ item$

This is then calculated as:

$P_{20} = 1st\ Item +0.8(2nd\ Item - 1st\ Item)$

$P_{20} = 16 + 0.8*(21 - 16)$

$P_{20} = 16 + 0.8*5$

$P_{20} = 16 + 4$

$P_{20} = 20$

Solving (b): The 25th percentile

This is calculated as:

$P_{25} = 25 * \frac{N +1}{100}$

$P_{25} = 25 * \frac{8 +1}{100}$

$P_{25} = 25 * \frac{9}{100}$

$P_{25} = \frac{25 * 9}{100}$

$P_{25} = \frac{225}{100}$

$P_{25} = 2.25\ th$

This is then calculated as:

$P_{25} = 2nd\ item + 0.25(3rd\ item-2nd\ item)$

$P_{25} = 21 + 0.25(24-21)$

$P_{25} = 21 + 0.25(3)$

$P_{25} = 21 + 0.75$

$P_{25} = 21.75$

Solving (c): The 65th percentile

This is calculated as:

$P_{65} = 65 * \frac{N +1}{100}$

$P_{65} = 65 * \frac{8 +1}{100}$

$P_{65} = 65 * \frac{9}{100}$

$P_{65} = \frac{65 * 9}{100}$

$P_{65} = \frac{585}{100}$

$P_{65} = 5.85\th$

This is then calculated as:

$P_{65} = 5th + 0.85(6th - 5th)$

$P_{65} = 27 + 0.85(28 - 27)$

$P_{65} = 27 + 0.85(1)$

$P_{65} = 27 + 0.85$

$P_{65} = 27.85$

Solving (d): The 75th percentile

This is calculated as:

$P_{75} = 75 * \frac{N +1}{100}$

$P_{75} = 75 * \frac{8 +1}{100}$

$P_{75} = 75 * \frac{9}{100}$

$P_{75} = \frac{75 * 9}{100}$

$P_{75} = \frac{675}{100}$

$P_{75} = 6.75th$

This is then calculated as:

$P_{75} = 6th + 0.75(7th - 6th)$

$P_{75} = 28 + 0.75(30- 28)$

$P_{75} = 28 + 0.75(2)$

$P_{75} = 28 + 1.5$

$P_{75} = 29.5$

7 0

3 years ago