Answer: I got's you lol
A≈13.85cm²
And the radius is 2.1
Step-by-step explanation:
Hope this helps let me know :)
Multiply each throughout!
=x^2+6x+8x+48
then arrange accordingly
x^2+14x+48
remember that in quadratic equation that you should have a squared (a) variable and a coefficient(b) and just a raw value (c)
A. First you must start by plugging in your equation solve Y = 2(5) + 1 then you must simplify by solving your 2×5+ 1 and then you end up with Y equals 11
B. Again plug in your equation Y = 2(-5) + 1 then you must simplify by solving your 2×-5+ 1 and then you end up with Y equals -10+ one which simplifies to y = -9
I hope this helps
Answer:
81
Step-by-step explanation:
[character limit thing]
Recall that for all t,
cos²(t) + sin²(t) = 1
Now,
x = 5 cos(t) - 7 ⇒ (x + 7)/5 = cos(t)
y = 5 sin(t) + 9 ⇒ (y - 9)/5 = sin(t)
so that substituting into the identity above, we get
((x + 7)/5)² + ((y - 9)/5)² = 1
which we can rewrite as
(x + 7)²/25 + (y - 9)²/25 = 1
(x + 7)² + (y - 9)² = 25
and this is the equation of a circle centered at (-7, 9) with radius 5.
