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3 years ago

Ok if you have 734

Mathematics

1 answer:

White raven [17]3 years ago

5 0

The answer you will need is seven hop I was helpful do me a favor and click on thank on the bottom

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What is 0.2 as a fraction

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It’s 2/10 there you go since there’s no 0 infort of the 2 it’s always a 10

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Find the center and the radius of the circle with the equation: x^2 - 2x + y^2 + 4y + 1 = 0

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In arithmetic sequence the first term is 5 and the common difference is 4. Determine the 6th term of sequence

Harlamova29_29 [7]

Answer:

The 6th term of the sequence is 25

Step-by-step explanation:

first term = a = 5

common difference = d = 4

The nth term of a sequence is

T_n = a + (n - 1)d

Therefore, the 6th term of the sequence is

T_6 = a + (6 - 1)d

T_6 = a + 5d

T_6 = 5 + 5(4)

T_6 = 5 + 20

T_6 = 25

3 0

3 years ago

How do you answer this question:

Maurinko [17]

66527273848 A. Aaaaaaaaaaaaaaaaa

5 0

3 years ago

pls help will give brainliest Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Base

kaheart [24]

Answer:

First "order of operations" mistake: step 2

First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

$\left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}$

for x = -1 and y = 2.

Her work seems to be ...

Step 1

$\text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}$

Step 2

$\text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}$

Step 3

$\text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}$

Step 4

$\text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}$

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

$\left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}$

We expect your answer is supposed to be Step 4.

7 0

3 years ago