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pogonyaev
3 years ago
14

Subtract these polynomials.

Mathematics
1 answer:
Ivanshal [37]3 years ago
8 0

Answer:

The correct answer for this question is D. -3x^2+11x+14

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Find the 15th term of the arithmetic sequence whose common difference is d=9 and whose first term is a, = 2.
Alenkinab [10]
Nose rkrbtje de donde salió la luz de
6 0
3 years ago
At a local print shop, 18 copies can be made for $6. At this rate, how much would it
Ber [7]

Answer: to make 78 copies it cost 26 dollars.

Step-by-step explanation:

18 copies - 6 dollars

78 copies - x dollars

Hence,

\displaystyle\\x=\frac{78*6}{18} \\\\x=\frac{26*3*6}{3*6} \\\\x=26 \ dollars

5 0
2 years ago
What is a fraction pair that is equivalent to 2/15 and 4/9, and in which both fractions have a
Vesnalui [34]

Answer:

  6/45 and 20/45

Step-by-step explanation:

The least common denominator is the least common multiple (LCM) of 9 and 15.

The factors of those numbers are ...

  9 = 3·3

  15 = 3·5

The LCM is the product of the unique factors to their highest powers:

  3·3·5 = 45

__

To make 2/15 have a denominator of 45, we need to multiply by 3/3:

  2/15·3/3 = 6/45

To make 4/9 have a denominator of 45, we need to multiply by 5/5:

  4/9·5/5 = 20/45

The desired fraction pair is 6/45 and 20/45.

7 0
3 years ago
A bee flies at 9 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 13 ​minutes, and then
Kobotan [32]

Complete Question

A bee flies at 9 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 13 ​minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 16 minutes. What equation can you use to find the distance of the flowerbed from the hive?

Answer:

The equation is 960  = \frac{Z}{9}+ \frac{Z}{6} + 780

Step-by-step explanation:

From the question we are told that

The velocity of the bee is v =  9ft/s =

The duration on the flowerbed is t =  13 \  minutes  =  780 \  s

The velocity back to his hive is u = 6ft / s

The total time away from it hive is t_t  =  16 \  minutes  =  960  \ s

Now let assume the distance of the flower bed from the hive is Z

Generally the time taken for the bee to travel to the flower bed from its hive is

t_1 =  \frac{Z}{9}

The time taken for the bee to fly back to his hive is

t_2 =  \frac{Z}{6}

Generally the total time the bee spent outside of his house is mathematically represented as

t_t  =  t_1 + t_2 +  t

=> 960  = \frac{Z}{9}+ \frac{Z}{6} + 780

6 0
3 years ago
Please help me out. precalc math. will report if answer is n/a
rjkz [21]

a is the correct answer I Hope it help

3 0
3 years ago
Read 2 more answers
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