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alukav5142 [94]
3 years ago
10

Need help fast don't understand both A and B show work please

Mathematics
1 answer:
Shkiper50 [21]3 years ago
5 0
Problem A
Usually the number of bits in a byte is 8 or 16 or 32 and recently 64. You don't have to write a formula to restrict it to this number of bits. You are not asked to do so. The general formula is 2^n - 1 for the problem of Millie and her golden keys. Somehow the system can be made to choose the right number of bits. Apple IIe s for example, used 8 bits and there was a location that told the processor that fact.

2^n - 1 <<<<< Answer

Problem B
In this case n = 4
2^n - 1 = 2^4 - 1 = 16 - 1 = 15


Millie can collect 15 keys <<<<<< Answer
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The question is below:​
Sonja [21]

Answer:

x = 19.5, RQS=43

Step-by-step explanation:

It is important to note that RQS and TQS are supplementary, meaning their angles will add up to 180. Knowing this, we can create and solve the equation to find x..

(2x+4) + (6x+20) = 180

8x + 24 = 180

8x = 156

x = 19.5

Now that we know the value of x, we can substitute it into the equation for RQS, 2x+4.

2(19.5)+4

39+4

43

Hope this helped!

4 0
3 years ago
Read 2 more answers
If a line has a slope of -4 and a u intercept of 1, which of the following is it's graph?
3241004551 [841]
Well. I can't see the picture. But it would be decreasing at a rate of 4 so pick a point on the any line move over to the right one, then down four. And for the y intercept the line would intersect the y axis at positive one. Sorry if that's confusing
3 0
3 years ago
Determine the area of the triangular ABC with AC=5cm and height DB=30 mm.<br>​
Lady_Fox [76]

Answer:

750 mm²

Step-by-step explanation:

<h3>Area of triangle:</h3>

To find the area of the triangle, multiply the base and height and then divide the result by 2.

       \sf \boxed{\bf Area \ of \ triangle = \dfrac{1}{2}*base *height}

base = AC = 5 cm = 50 mm

height = DB = 30 mm

                                       \sf = \dfrac{1}{2}*50*30\\\\= 25 *30\\\\= 750 \mm^2

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Vanyuwa [196]
Y = 3x + 5
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g^-1(x) = (x - 5)/3
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