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Gekata [30.6K]
3 years ago
9

Whhhhhhhhhhhhhhyyyyyyyyyyyyyyyyyyy

Mathematics
1 answer:
Anarel [89]3 years ago
7 0

Answer:

3x^{2}

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What is the reminder when (3x^3-2x^2+4x-3) is divided by (x^2+3x+3)
NARA [144]
(For full answer you might have to go to the comments)

Answer: 28x+30

Explanation: we divide (3x^3-2x^2+4x-3) by (x^2+3x+3) Using long division
3x-11
___________________
(x^2+3x+3) 3x^3-2x^2+4x-3


-(3x^3+9x^2+9x)
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-11x^2-5x-3

-(-11x^2-33x-33)
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28x+30

So our remainder will be 28x+30
5 0
3 years ago
Find the lateral and total surface area for the cone. If necessary, round to the nearest tenth and leave the
bija089 [108]

9514 1404 393

Answer:

  • 262.2π cm²
  • 392.16π cm²

Step-by-step explanation:

The lateral surface area is the product of half the circumference, and the slant height:

  LA = πrh = π(11.4 cm)(23 cm) = 262.2π cm²

The total surface area adds the area of the base to that:

  A = πr² +LA = π(11.4 cm)² +262.2π cm² = (129.96 +262.2)π cm²

  A = 392.16π cm²

3 0
3 years ago
The sum of two consecutive integers is 65. Find the two integers.
Oliga [24]
32+33=65 
60/2 is 30, so they have to be in their thirties. Then 2+3=5, therefore they must be 32 and 33
7 0
3 years ago
5. Find the change in temperature: from -1°F to -20°F
kap26 [50]

Answer:

-19

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
(2) The population density of a region in Alaska is 3,000 people/200 mi? Which of the
Vesna [10]

Answer:

15 people/mi

Step-by-step explanation:

The population density of a region in Alaska is 3,000 people/200 mi.

We need to find the equivalent to the population density of this Alaskan region.

x=\dfrac{3000\ \text{people}}{200\ \text{mi}}\\\\x=\dfrac{30\ \text{people}}{2\ \text{mi}}\\\\x=\dfrac{15\ \text{people}}{\text{mi}}

So, the correct option is (c) "15 people/mi"

8 0
3 years ago
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