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slamgirl [31]
3 years ago
8

I need help I’m not sure

Mathematics
1 answer:
Daniel [21]3 years ago
3 0

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{3}~,~\stackrel{y_1}{5})\qquad  (\stackrel{x_2}{-6}~,~\stackrel{y_2}{-6}) \qquad \left(\cfrac{ x_2 +  x_1}{2}~~~ ,~~~ \cfrac{ y_2 +  y_1}{2} \right) \\\\\\ \left( \cfrac{-6+3}{2}~~,~~\cfrac{-6+5}{2} \right)\implies \left(\cfrac{-3}{2}~~,~~\cfrac{-1}{2}  \right)\implies \left( -1\frac{1}{2}~,~-\frac{1}{2} \right)

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Answer:

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Step-by-step explanation:

f(x)=g(x)-1 since was shifted down 1 unit                                        x^3-1

f(x)=g(x)+1 would have been a shift up of 1 unit                             x^3+1

f(x)=g(x-1) shifted right 1 unit                                                            (x-1)^3

f(x)=g(x+1) shifted left one unit                                                        (x+1)^3

Anyways the answer is f(x)=x^3-1

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lapo4ka [179]

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