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jek_recluse [69]
3 years ago
6

For a sample of 100 students, the median number of text messages sent per day is 90, the first quartile is 78, and the third qua

rtile is 102. Select all of the answers that create a true statement.
Approximately 25 students in the sample send
Mathematics
2 answers:
Igoryamba3 years ago
7 0

Answer:

between 78 and 102 texts and more than 78 text messages.

Step-by-step explanation:

the range of it is 102-178, so its between there, and its more than 78 as well if the range goes up to 102

Valentin [98]3 years ago
4 0

Answer:

The correct answers are:

-Less than 78

-More than 102

-Between 78 and 90

-Between 90 and 102

Step-by-step explanation:

Quartiles show where 25% of the population lies. Since the bottom quartile is 78, we know 25% would be under. Since 102 is the upper quartile, 25% would be above.

We can also create further quartiles between the median and those quartiles.

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How many solutions does 2.3y+3.2-y=2.1+1.3y+1.1 have?
jeka57 [31]
1.3y +3.2 = 1.3y +3.2

we notice that both sides of the equation are identical. So substitute y with any value and the equation would still be correct.

y has infinite solutions.
6 0
3 years ago
An air transport association surveys business travelers to develop quality ratings for transatlantic gateway airports. The maxim
Flura [38]

Answer:

The 95% confidence interval estimate of the population mean rating for Miami is (6.0, 7.5).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population mean, when the population standard deviation is not provided is:

CI=\bar x \pm t_{\alpha/2, (n-1)}\cdot \frac{s}{\sqrt{n}}

The sample selected is of size, <em>n</em> = 50.

The critical value of <em>t</em> for 95% confidence level and (<em>n</em> - 1) = 49 degrees of freedom is:

t_{\alpha/2, (n-1)}=t_{0.05/2, 49}\approx t_{0.025, 60}=2.000

*Use a <em>t</em>-table.

Compute the sample mean and sample standard deviation as follows:

\bar x=\frac{1}{n}\sum X=\frac{1}{50}\times [1+5+6+...+10]=6.76\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{49}\times 31.12}=2.552

Compute the 95% confidence interval estimate of the population mean rating for Miami as follows:

CI=\bar x \pm t_{\alpha/2, (n-1)}\cdot \frac{s}{\sqrt{n}}

     =6.76\pm 2.000\times \frac{2.552}{\sqrt{50}}\\\\=6.76\pm 0.722\\\\=(6.038, 7.482)\\\\\approx (6.0, 7.5)

Thus, the 95% confidence interval estimate of the population mean rating for Miami is (6.0, 7.5).

7 0
2 years ago
Complete the pattern.
Leni [432]

answer:

17,060 is the answer

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3 years ago
What would the graph of the solution to the following inequality look like?
yan [13]

Answer: A. An OPEN circle on the number 5 and an arrow shading to the RIGHT.

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2 years ago
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Alex_Xolod [135]

Answer:

What is a factor?

Step-by-step explanation:

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3 years ago
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