Answer:
The domain: all real numbers;
The range: 
Step-by-step explanation:
The graph of the function y=|x| opens up and has a vertex at (0,0). If the graph of an absolute value function opens up and has a vertex of (0, -3), then the function has an expression
y=|x|-3 (see attached diagram).
The domain of the parent function y=|x| is the set of all real numbers, then the domain of the function y=|x|-3 is the set of all real numbers too.
The range of the parent function y=|x| is 
then the range of the function y=|x|-3 is
The LCD = 6x^2y^3 ( because LCD of 3 and 6 = 6, LCD of x^2 and x = x^2 and LCD of y and y^3 = y^3)
now divide 3x^2y into the LCD then multiply this by 5 to get the first term in the numerator and do similar process to get second term, so we get:-
5(2y^2) - 4(x)
------------------
6x^2y^3
= 2( 5y^2 - 2x)
-----------------
6x^2y^3
= 5y^2 - 2x
-----------
3x^2y^3
We would use the sine function because we have an angle the hypotenuse, and the unknown opposite side.
sin(x)=opposite/hypotenuse
sin(60)=x/30
√3/2=x/30 (cross multiply)
30*√3/2=x (divide numerators and denominators by 2)
x=15√3 ft.
So the correct answer is A
Hope this helps
Answer:
2n + 1 to find the first odd number.
Step-by-step explanation:
that is it
I think it would be A because if you multiply the square by a 30 thinking there all the same space between it will give u 120 square yards
