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Lina20 [59]
4 years ago
11

Which of the following is the most appropriate unit to describe the time you can drive a car based on the amount of gas?

Mathematics
2 answers:
Anton [14]4 years ago
7 0
I believe the answer to the question is A. This is because the minutes rely on the amount of gas that you have.
3241004551 [841]4 years ago
6 0
Yo i think it's A, due to the fact that the more gallons you have, the more minutes you can drive. hope this helps, have an amazing day :)
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What is five thousand two hundred twenty-five and seventy-two thousandths expressed in standard form?
miv72 [106K]
5,225.072 is the standard form. 
6 0
3 years ago
Read 2 more answers
Please help me, solve for x tysm whoever does it without trollling or just answers to get points
iris [78.8K]

Answer:

x = 9/8

Step-by-step explanation:

You would use proportions in this case.

9/9+x = 1/x

9x = 9 + x

8x = 9

x = 9/8

3 0
3 years ago
What is the average rate of change from -3 to 0 of the function represented by the graph?
lbvjy [14]

Average rate of change = change in y ÷ change in x

We already know the change in x because we are measuring the x values from -3 to 0.

change in x = 0-(-3) = 3

To find the change in y find the difference between the corresponding y-values when x=0 and when x=-3.

change in y = 0.5-2 = -1.5

average rate of change = -1.5/3 = -0.5

answer: -0.5

3 0
3 years ago
. Carlos and his family left for the amusement park at 7:35a.M. The trip took 1 hour 45 minutes. What time did they arrive?
Alex

Answer:

they arrived at 9:20 A.M.

Step-by-step explanation:

If you look at the time they left and how much time it took for them to arrive all you have to do is add 1:45 to 7:35 while adding in time sense so add the 5 to 35 to get 7:40 then add 20 from the 40 to the other 40 to get 8:00 then you can add the remaining 20 to get 8:20 now you can add the hour to make it 9:20 A.M.

6 0
3 years ago
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Drag the tiles to the correct boxes to complete the pairs.
olchik [2.2K]

Answer:

1)(2m^2-4m)/2(m-2) = m (fourth blank)

2)m^2-2m+1/m-1= m-1 (second blank)

3)m^2-3m+2/m^2-m= (m-2)/m (first blank)

4)m^2-m-2/m^2-1=(m-2)/(m-1)    (third blank)

Step-by-step explanation:

1)

(2m^2-4m)/2(m-2)

=[2m(m-2m)]/2(m-2)

= 2m/2

=m

2)

m^2-2m+1/m-1

= (m-1)^2/(m-1)

=(m-1)(m-1)/(m-1)

=(m-1)

3)

m^2-3m+2/m^2-m

=m^2-m-2m+2/m(m-1)

=m(m-1)-2(m-1)/m(m-1)

= (m-1)(m-2)/m(m-1)

=(m-2)/m

4)

m^2-m-2/m^2-1

=m^2+m-2m-2/(m+1)(m-1)

=m(m+1)-2(m+1)/(m+1)(m-1)

=(m+1)(m-2)/m+1)(m-1)

=(m-2)/(m-1) !

5 0
3 years ago
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