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Scorpion4ik [409]
3 years ago
9

Emily and Lars went scuba diving in the ocean together. Emily dove to a depth of -95 feet, while Lars dove

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
3 0

Answer:

Emily

Step-by-step explanation:

The lower the number is the lower it is

Its just like temperature

Please MARK BRAINLIEST

max2010maxim [7]3 years ago
3 0

Answer:

emily

Step-by-step explanation:

-95 feet is 6 feet deeper than -89 feet

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What is the distance between the points<br> (7, 8) and (-8, 0) on a coordinate grid?
denpristay [2]

Answer:

-15,-8

Step-by-step explanation:

I counted from 7 to -8, so that was -15.Then counted from 8 to 0, and that was -8. So that's how I got my answer!!

8 0
2 years ago
Please answer this ASAP please!!!
miskamm [114]

Answer:

1/12

Step-by-step explanation:

There are 36 possible outcomes

Out of the 36 there are only 3 where the sum is 4 that is (1,3),(2,2),(3,1)

Hence probability= 3/36 which equals to 1/12

8 0
3 years ago
PLEASE HELP ASAP 30 POINTS!
sveta [45]

Answer:

-4/3

Step-by-step explanation:

6 0
10 months ago
Read 2 more answers
Simplify the expression -3 ÷ (-2/5 ​
Harlamova29_29 [7]

Answer:

7.5

Step-by-step explanation:

To solve this expression, we can use PEMDAS or order of operations.

<u>Parenthesis</u>

<u>Exponents</u>

<u>Multiplication>Division (Depends on which comes first from left to right)</u>

<u>Addition>Subtraction (See Multiplication>Division)</u>

So First, lets solve the <u>Parenthesis</u>. -2/5=-.4

So now, our equation is -3/-.4

There is no exponents or multiplication, so lets just <u>Divide</u>.

-3/-.4=7.5

The solution is 7.5

Hope this helps!

6 0
3 years ago
What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Natasha2012 [34]

Answer:

x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}  are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

2x^2-10x-3

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}

General form of quadratic equation is ax^2+bx+c

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

D=\sqrt{(-10)^2-4(2)(-3)}

\Rightarrow D=\sqrt{100+24}=\sqrt{124}

Now substituting D in  x=\frac{b^2\pm\sqrt{D}}{2a} we get

x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}

x=\frac{100\pm\sqrt{124}}{4}

x=\frac{100\pm2\sqrt{31}}{4}

x=\frac{50\pm\sqrt{31}}{2}

Therefore, x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}



5 0
3 years ago
Read 2 more answers
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