The greatest common factor for 5 and 10 is 5
7.11 because 1.58(3.50)=5.53 + 1.58 = 7.11
Answer:
420.9
Step-by-step explanation:
420.86827 ≈ 420.9 because we need to round to one decimal place.
Since 6 is greater than 5, we round 8 up to make it 9
420.9
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Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S =
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer