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yawa3891 [41]
4 years ago
13

You cut 63 meters of rope into 9 equal pieces. How long is each equal piece of rope?

Mathematics
2 answers:
Bingel [31]4 years ago
7 0
7 meters. 63/9 =7 i think is right
Rama09 [41]4 years ago
4 0
7 Meters. 63/9=7

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What are the steps to solve this problem? 0.000027 divided 0.000009. explain how to use scientific notation?
Neporo4naja [7]
Put it into standard form so you would have

27x10¯6 divided by 9x10¯6

Then you can divide the numbers so 27/9 = 3

Then to divide the powers you just take them away so - 6--6 = - 6 +6 = 0

Therefore the answer is just 3
6 0
4 years ago
By what percent will a fraction increase if its numerator is decreased by 30% and its denominator is decreased by 50%?
Alex Ar [27]
(X + .3X) / (X - 0.5X) = 1.3X/0.5X
1.3/0.5 = 2.6
2.6 x 100 = 260 %
6 0
3 years ago
Please could someone help with this ? Thankyou
katovenus [111]

Answer:

1 2/7

Step-by-step explanation:

4.5:3 1/2

45/10 ÷ 7/2

45/10 x 2/7

90/70=9/7

=1 2/7

4 0
3 years ago
Read 2 more answers
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

               Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 2.65

           \sigma  = standard deviation = 0.85

            n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

    P(X bar <= 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z < 2.06) = 0.98030

 P(X bar <= 2.65) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3)  = 0.98030 - 0.5 = 0.4803 .

                                                                             

8 0
3 years ago
to determine a student's grade, a teacher throws out the lowest grade obtained on 5 tests, averages the remaining grades, and ro
RoseWind [281]

Answer:

B grade

Step-by-step explanation:

75 + 90 + 88 + 86 = 339

339/4 = 84.75

Grade B = 80-89%

3 0
3 years ago
Read 2 more answers
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