3 years ago

is the sum of two polynomials of degree 5 always a polynomial of degree 5? Give an example to explain your answer

1 answer:

7 0

A counter example is

f(x)=5x^5+2x^3+3x
g(x)=-5x^5-x^4+x^2-4

Then f(x)+g(x) = -x^4+2x^3+x^2+3x-4 which is a polynomial of degree 4.

So the answer is no. Counter-example is given above.

You might be interested in

Select the expressions that are equivalent to 12n - 8. Select all that apply.

morpeh [17]

A.3n+4+3n+4+4n

=3n+3n+4n+4+4

=10n+8

B.11n+4+n-12

=11n+n+4-12

=12n-8

C.6(6n-2)

=36n-12

D.4(3n-2)

=12n-8

E.4n+22-12+8n

=4n+8n+22-12

=12n+10

so,B and D are the expressions that are equivalent to 12n-8.

3 0

2 years ago

When adding vegetables to a footlong (30 cm) sandwich, how many ounces or slices of vegetables do you use? select all that apply

MA_775_DIABLO [31]

A footlong sandwich will fit other ingredients besides vegetables, such as 4 slices cheese or 4 strips of beacon, but if we only talk about vegetables, you can 1.5 oz. Lettuce and 1 oz. Onion, 6 slices each; Tomato, cucumber, pickles, pepper, olives, jalapeños.

7 0

4 years ago

Solve the equation by completing the square.Round to the nearest hundredth if necessary. X^2–x–7=0

lesya [120]

NOTE: $\left(x-\dfrac{1}{2}\right)^2=x^2-x+\dfrac{1}{4}$

$x^2-x-7=0 \\ \\ \underbrace{x^2-x+\frac{1}{4}}_{\left(x-\frac{1}{2}\right)^2}-7\dfrac{1}{4}=0 \\ \\ \\ \left(x-\frac{1}{2}\right)^2=7\frac{1}{4}=\frac{29}{4} \qquad /\sqrt{}\\ \\ \left|x-\frac{1}{2}\right|=\dfrac{\sqrt{29}}{2} \\ \\ x_1=\dfrac{1}{2}-\dfrac{\sqrt{29}}{2} \approx -2.19 \\ \\ x_2=\dfrac{1}{2}+\dfrac{\sqrt{29}}{2} \approx 3.19$

ANSWER: c)

5 0

3 years ago

a year ago the price of a car was RM41,000 now its price depreciates by 14%.How much is the car now?

Readme [11.4K]

Answer:

$35260

1% of 41,000 = 410

410 x 14 = 5740

41,000 - 5740 = 35260

8 0

3 years ago

Using sq root property. 2x^2+36+0

mezya [45]

It’s 2.&:&/8/8/8&/keisjsisk

5 0

3 years ago