The OC level is primarily used as a regional ISP backbone, and occasionally by very large hospitals, universities, or other major enterprises is <u>OC-48.</u>
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<h3>What is the greatest amount of throughput provided by an OC 12?</h3>
OC-12 is a network line with communication speeds of up to 622.08 Mbit/s (payload: 601.344 Mbit/s; overhead: 20.736 Mbit/s). OC-12 lines are generally used by ISPs as wide area network (WAN) connections.
<h3>When using frame relay What is the appellation of the identifier?</h3>
A data-link connection identifier (DLCI) determines the Frame Relay PVC. Frames are routed through one or more virtual circuits determined by DLCIs.
Each DLCI has a permanently configured switching path to a particular destination
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A. How many marathons you have run, because it doesn't relate to the job you're applying for.
Answer:
Positive media attention can transform communities in unexpected ways.
Explanation:
According to the given excerpt, it is narrated that Kathleen wrote about a town called Abbston that was recently overwhelmed by tourists as a result of the news article by a TV travel editor who wrote about the town.
Therefore, the best concluding sentence for the paragraph would be that positive media attention can transform communities in unexpected ways.
Answer:third stage of parent-infant attachment
Explanation:
Answer:
// program in C.
// headers
#include <stdio.h>
// headers
#include <stdlib.h>
// headers
#include <limits.h>
// main function
int main(int argc, char** argv)
{
// read value of N from command line arguments
int N=atoi(argv[1]);
// variables
int max=INT_MIN;
// variable
int min=INT_MAX;
int rA[N],i;
// fill the array with random number
for(i=0;i<N;i++)
{
// generate random number from -50 to +50
rA[i]=rand()%101-50;
// find the Maximum
if(rA[i]>max)
max=rA[i];
// find the Minimum
if(rA[i]<min)
min=rA[i];
}
// print values of array
printf("values of the array are:");
for(i=0;i<N;i++)
{
printf("%d ",rA[i]);
}
// print Maximum
printf("\nMaximum value is:%d",max);
// print Minimum
printf("\nMinimum value is:%d",min);
return 0;
}
Explanation:
Read value of N from command line.Then create an array of size N.Fill the array with random number from -50 to +50.Then find the Maximum of all the elements and assign it to variable "max" and find Minimum from all and assign it to variable "min". then print all the elements of the array, Minimum and Maximum.
Output:
command line argument=10
values of the array are:-18 -18 4 -38 2 6 -42 -20 -6 44 -6 -11 15 -31 1
Maximum value is:44
Minimum value is:-42
