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Lelechka [254]
3 years ago
6

Consider a physical transmission medium of capacity C bits/sec between two stations that have I bits of information sent/receive

d in chunks of R-bit packets (where I ≫ R and each packet has a header of size h bits). The inter-packet resynchronization delay in the clock hardware is d sec, which requires that two successive packet transmissions be separated by at least d sec. What is the total time to send the I bits of information ? Assuming that the signal propagation delay is negligible.

Computers and Technology
1 answer:
levacccp [35]3 years ago
5 0

Answer:

Check the explanation

Explanation:

when calculating the total time to send the I bits of information or The packet delivery time or latency which can be said to be the amount of time from when the first bit leaves the point of transmission until the last is received. When it comes to a physical link, it can be computed or determined as: Packet delivery time = Transmission time + Propagation delay.

Kindly check the attached image below to get the step by step explanation to the above question.

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Explanation:

Some examples are:

call by value

#include <stdio.h>  

void swap(int, int);

int main()

{  int a = 10, b= 20;

 swap(a, b);

 printf("a: %d, b: %d\n", a, b);

}  

void swap(int c, int d)

{

 int t;

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}  

OUTPUT

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//call by reference

#include <stdio.h>

 void swap(int*, int*);

 int main()

{

 int a = 10, b = 20;

 swap(&a, &b);   //passing the address

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}

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