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Lelechka [254]
3 years ago
6

Consider a physical transmission medium of capacity C bits/sec between two stations that have I bits of information sent/receive

d in chunks of R-bit packets (where I ≫ R and each packet has a header of size h bits). The inter-packet resynchronization delay in the clock hardware is d sec, which requires that two successive packet transmissions be separated by at least d sec. What is the total time to send the I bits of information ? Assuming that the signal propagation delay is negligible.

Computers and Technology
1 answer:
levacccp [35]3 years ago
5 0

Answer:

Check the explanation

Explanation:

when calculating the total time to send the I bits of information or The packet delivery time or latency which can be said to be the amount of time from when the first bit leaves the point of transmission until the last is received. When it comes to a physical link, it can be computed or determined as: Packet delivery time = Transmission time + Propagation delay.

Kindly check the attached image below to get the step by step explanation to the above question.

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Answer:

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<h2>Answer:</h2>

//import the Scanner class to allow for user input

import java.util.Scanner;

//Begin class definition

public class FirstAndLast{

   //Begin the main method

    public static void main(String []args){

       

       

       //****create an object of the Scanner class.

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       Scanner input = new Scanner(System.in);

       

       //****create a prompt to tell the user what to do.

       System.out.println("Enter the string");

       

       //****receive the user's input

       //And store it in a String variable called 'str'

       String str =  input.next();

       

       //****get and print the first character.

       //substring(0, 1) - means get all the characters starting

       //from the lower bound (index 0) up to, but not including the upper

       //bound(index 1).

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       System.out.print(str.substring(0,1));

       

       //****get and print the last character

       //1. str.length() will return the number of character in the string 'str'.

       //This is also the length of the string

       //2. substring(str.length() - 1) - means get all the characters starting

       // from index that is one less than the length of the string to the last

       // index (since an upper bound is not specified).

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       System.out.print(str.substring(str.length()-1));

       

       

       

    }  // end of main method

   

} //end of class definition

<h2>Explanation:</h2>

The code has been written in Java and it contains comments explaining important parts of the code. Kindly go through the comments.

The source code and a sample output have also been attached to this response.

To run this program, copy the code in the source code inside a Java IDE or editor and save it as FirstAndLast.java

Download java
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
4c53f66d970acf88b251b2cf41bcdaf6.png
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