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snow_tiger [21]
3 years ago
6

In a file-oriented information system, a transaction file ____.

Computers and Technology
1 answer:
Dima020 [189]3 years ago
8 0
Is it a multiple choice answer?
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Project planning output is :
-Dominant- [34]

Answer:

A

Explanation:

The main output of Project palnning is project plan.

5 0
3 years ago
Sites like Zillow get input about house prices from a database and provide nice summaries for readers. Write a program with two
qaws [65]

Answer:

Se explaination

Explanation:

/Declaring variables

integer currentPrice

integer lastMonthPrice

integer changeLastMonth

float mortagage

//Reading input

currentPrice = Get next input

lastMonthPrice = Get next input

//Calculating price change

changeLastMonth = currentPrice - lastMonthPrice

//Calculating mortagage

mortagage = (currentPrice * 0.051) / 12

//Printing output

Put "This house is $" to output

Put currentPrice to output

Put "\nThe change is $" to output

Put changeLastMonth to output

Put " since last month." to output

Put "\nThe estimated monthly mortgage is $" to output

Put mortagage to output

3 0
3 years ago
What is your favorite video that Markiplier did with Bob, Wade, and Jack?
Lana71 [14]

Answer:

Probably my all-time favorite Unus Annus video. Ethan, not a professional swimmer or swimming instructor, “teaches” Mark how to swim.

Explanation:

6 0
3 years ago
You will complete 3 tasks. Task 1: Determine if the input number is prime or not You will ask the user for an integer You will d
GuDViN [60]

Answer:

Program is written in C++

#include<iostream>

using namespace std;

int main()

{

//1. Prime Number

int num;

cout<<"Input Number: ";

cin>>num;

int chk = 0;

for(int i =2; i <num;i++)

{

 if(num%i==0)

 {

  chk = 1;

  break;

 }

}

if(chk == 0)

{

 cout<<num<<" is prime"<<endl;

}

else

{

 cout<<num<<" is not prime"<<endl;

}

//2. Greatest Common Factor

int num1, num2, x, y, temp, gcf;  

cout<<"Enter two numbers: ";

cin>>num1;

cin>>num2;

x = num1;

y = num2;

while (y != 0) {

   temp = y;

   y = x % y;

   x = temp;

 }

 gcf = x;

 cout<<"Greatest Common Factor: "<<gcf<<endl;

 

// 3. LCM  

cout<<"Enter two numbers: ";

cin>>num1;

cin>>num2;

x = num1;

y = num2;

while (y != 0) {

   temp = y;

   y = x % y;

   x = temp;

 }

 gcf = x;

 int lcm =(num1 * num2)/gcf;

cout<<"Least Common Multiple: "<<lcm<<endl;

return 0;

}

Explanation:

<em>I've added the full source code as an attachment where I make use of comments to explain some lines</em>

Download cpp
6 0
3 years ago
the server encountered an internal error or misconfiguration and was unable to complete your request.
mezya [45]
Error 404 - didn’t found
4 0
3 years ago
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