The effectiveness of using thicker bags are:
- It has the lowest environmental impact in terms of any other disposable bag.
- It can be used three to six more times.
- It is environmentally sustainable.
<h3>What is the effect of thicker plastic bags have on the environment?</h3>
The use of plastic bags is known to have some form of detrimental effects on the such as animal choking, pollution, and others.
Conclusively, Note that thicker bags needs a lot of plastic to be able to produce it and it goes to waste even if a person do not use it again.
Learn more about environment from
brainly.com/question/17413226
no here r the ranks:Beginner
Helping Hand
Virtuoso
Expert
and genius
Answer:
its easy
Explanation:
there are are 5 main rules
in binary there are 2 number 0 and 1
0 + 0 = 0
0 + 1 = 1
1+0=1
1+1=0 carry 1
e . g
1 1 1
1 0 1 0 1 0
+ 1 1 0 0 1 0
-------------------------
1 1 1 1 1 0 0
*in bold are the ones that you need to carry.
in decimal there are 10 possible numbers 0- 9
when you do 1 + 9 it becomes 10, this can be done easily, however if you do 1 + 9 in a table like above, you will get 0 for the first column and you will carry 1 to the next column .
in binary is the same idea but using on 2 numbers 1 and 0
e.g
1
1
+ 9
----------
1 0
*in bold are the ones that you need to carry.
hope it helps and good luck in your exam.
Answer:
#include <iostream>
using namespace std;
class Str{ ///baseclass
public :
string super_str;
string getStr()
{
return super_str;
}
void setStr(string String)
{
super_str=String;
}
};
class str : public Str{ //inheriting Str publicly
public :
string sub_str;
string getstr()
{
return sub_str;
}
void setstr(string String)
{
sub_str=String;
}
bool notstartswith()
{
int n=sub_str.length(); //to find length of substr
bool flag=false;
for(int i=0;i<n;i++) //Loop to check beginning of Str
{
if(super_str[i]!=sub_str[i])
{
flag=true;
break;
}
}
return flag;
}
};
int main()
{
str s; //object of subclass
s.setStr("Helloworld");
s.setstr("Hey");
if(s.notstartswith()==1) //checking if str is substring of Str
cout<<"Str does not start with str";
else
cout<<"Str starts with str";
return 0;
}
OUTPUT :
Str does not start with str
Explanation:
Above program is implemented the way as mentioned. for loop is being used to check the beginning of the str starts with substring or not.
