Answer:
See the explanation
Explanation:
Answer 1.
As given that in F1 all are short and white then it can be said according to Mendel's law that short and white are dominant over tall and purple.
Let S for short s for tall and W for white and w for purple allele.
So the genotype of short purple will be Ssww or SSww. So In first case Ssww self crossed then resultant offsprings will be,
................ Sw .................... sw
Sw ........ SSww ............. Ssww
sw ........ Ssww .............. ssww (tall and purple)
So from this 1/4 will be tall and purple while 3/4 will be short and purple.
In second case SSww only short purple progeny will appear.
Answer 2.
2. a) The female progeny will not show any trait because there are two X chromosome in females , so female offspring can be carrier but not show any trait in case of X- linked trait.
2. b) Half of male offsprings show trait because X is inherited from mother. So the chance of having X-linked recessive allele is 1/2.
2. c) The chance of having X linked affect allele in daughter is 1/2. So the chance of inheriting that X to son will be 1/2 so in total there is chance of 1/4 that son will be affected.
2. d) the chance of first child show this trait will be 1/4 in case of male offspring while 0 in case of female offspring.
Hope this helps!
Answer:
Im not 100% sure but I believe the answer is A
Explanation:
Answer:A man with pku marries a woman without any alleles for pku.There is little possibility that a child will inherit PKU
<u>Explanation: </u>
PKU Is Phenylketonuria results in less metabolism of amino acid. It might lead to a mental disorder or behavior problems. It is mostly Genetic.
If only one parent is suffering from it then there is little possibility that it will pass on to a child but if both the parents are having the problem of PKU then there are more chances that the child will also develop such a problem. It can be treated if we catch it at an early stage.
