Answer:
The first car is traveling at a speed of
s1=62 mi/hr.
The second car is traveling at a speed of s2=67 mi/hr.
Step-by-step explanation:
Let t be the amount of time the cars are traveling
s1=248/t and s2=268/t
We are told:
s1=s2-5
That is
248/t=268/t-5
⇒248=268- 5t
⇒5t=20
⇒t=4
s1=248/4=62
s2=268/4=67
19/20
19/20 = 0.95
0.9 < 0.95
Answer:
0.57142
Step-by-step explanation:
A normal random variable with mean and standard deviation both equal to 10 degrees Celsius. What is the probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit?
We are told that the Mean and Standard deviation = 10°C
We convert to Fahrenheit
(10°C × 9/5) + 32 = 50°F
Hence, we solve using z score formula
z = (x-μ)/σ, where
x is the raw score = 59 °F
μ is the population mean = 50 °F
σ is the population standard deviation = 50 °F
z = 59 - 50/50
z = 0.18
Probability value from Z-Table:
P(x ≤59) = 0.57142
The probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit
is 0.57142
Answer:
3025 is the answer directly I have solved bro
