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3 years ago

A circle mirror has a diameter of 12 inches. What is the area,in square inches, of the mirror?

1 answer:

5 0

Area of circle= pi times radius^2

diameter=2 times radius
radius=diameter/2
diameter=12
radius=12/2
radius=6

pi times r&+^2
pi times 6^2
pi times 36
aprox pi=3.14
113.04 in^2

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Solve the equation 7x-2(x-10)=40

bekas [8.4K]

Answer:

−

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−

)

7x{\color{#c92786}{-2(x-10)}}=40

7x−2(x−10)=40

−

Step-by-step explanation: therefore your answer would be x=4

BRAINLIEST PLEASE

5 0

2 years ago

Read 2 more answers

Amadahy wants to buy a card and two gifts for her friend. Cards cost 3.49 each and gifts cost $10.63 each. Amadahy has a 20$ bil

BartSMP [9]

Answer:

Given that Amadahy has a $ 20 bill, and wants to buy a card and two gifts for her friend, and knowing that each card costs $ 3.49 and each gift costs $ 10.63, the total cost of the 3 items would be $ 24.75 (10.63 x 2 + 3.49 ).

Therefore, she will not be able to purchase the products she wants, since she will need $ 4.75 to reach the amount necessary for it (24.75 - 20).

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3 years ago

A system of equations is shown below:

padilas [110]

Answer:

y=3

x=2

Step-by-step explanation:

i have answered it....feel free to ask if u don't get it

8 0

3 years ago

Solve the system of linear equations by graphing. y = –5/2 x – 7 x + 2y = 4 What is the solution to the system of linear equatio

Anestetic [448]

Keywords

system; linear equations; graphing; solution

we have

$y=-\frac{5}{2}x-7$ -------> equation A

$x+2y=4$

$x=4-2y$ ----> equation B

The system of linear equations is composed of equation A and equation B

Substitute the equation B in equation A

$y=-\frac{5}{2}[4-2y]-7$

$y=-10+5y-7$

$4y=17$

$y=17/4=4.25$

Find the value of x

$x=4-2[17/4]=-4.5$

The solution is the point $(-4.5,4.25)$

Using a graphing tool

see the attached figure

therefore

the answer is the option A

$(-4.5,4.25)$

4 0

2 years ago

Read 2 more answers

PLEASE HELP ME!

kotegsom [21]

Answer:

Bottom left graph

Step-by-step explanation:

We have to use what is called the zero-interval test [test point] in order to figure out which portion of the graph these inequalities share:

−2x + y ≤ 4 >> Original Standard Equation

+ 2x + 2x

_________

y ≤ 2x + 4 >> Slope-Intercept Equation

−2[0] + 0 ≤ 4

0 ≤ 4 ☑ [We shade the part of the graph that CONTAINS THE ORIGIN, which is the right side.]

$\displaystyle y > x + 2 \\ \\ 0 ≯ 2$ [We shade the part of the graph that does not contain the origin, which is the left side.]

So, now that we got that all cleared up, we can tell that the graphs share a region in between each other and that they both have POSITIVE RATE OF CHANGES [SLOPES], therefore the bottom left graph matches what we want.

** By the way, you meant $\displaystyle y > x + 2$ because this inequality in each graph is a dashed line. It is ALWAYS significant that you be very cautious about which inequalities to choose when graphing. Inequalities can really trip some people up, so once again, please be very careful.

I am joyous to assist you anytime.

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3 years ago