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3 years ago

A circle mirror has a diameter of 12 inches. What is the area,in square inches, of the mirror?

1 answer:

5 0

Area of circle= pi times radius^2

diameter=2 times radius
radius=diameter/2
diameter=12
radius=12/2
radius=6

pi times r&+^2
pi times 6^2
pi times 36
aprox pi=3.14
113.04 in^2

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Factor completely 12a^3d^2 – 6ad^3

lorasvet [3.4K]

Answer:

$12a^3d^2-6ad^3$

To factor an integer, we need to divide it by the ascending sequence of primes 2, 3, 5

In the end, the number of times each prime divides the original integer becomes its exponent.

Prime number 2 to the power of 2 equals 4 .

Prime number 3 to the power of 1 equals 3 .

$2^{2} \times 3\times a^{3} \times b^{2} -(2\times3)ad^{3}$

Result:- $6ad^2\left(2a^2-d\right)$

<u> OAmalOHopeO</u>

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3 years ago

Find the volume of a right circular cone that has a height of 18.6 m and a base with a radius of 15.5 m. Round your answer to th

ExtremeBDS [4]

This one should have come before the other one. We apply the cone formula

$V = \frac 1 3 \pi r^2 h$

$V = \frac 1 3 \pi(15.5)^2 (18.6) \approx 4679.6 \textrm{ cubic meters}$

4 0

2 years ago

Solve the system of linear equations. separate the x- and y- values with a coma. -9x+2y=-7

Iteru [2.4K]

Y = 1, x = 1 hope this helps!

5 0

3 years ago

Simplify and write the trig expression in terms of sin and cos

dsp73

We have:

$cot(-x)cos(-x)+sin(-x)=-\frac{1}{f(x)}$

Then we use trigonometric identities to change the negative sign of the trigonometric functions, so:

$-sin(x)-cot(x)cos(x)=-\frac{1}{f(x)}$

We clear f(x):

$f(x)=\frac{1}{sin(x)+cot(x)cos(x)}=\frac{1}{sin(x)+\frac{cos(x)}{sin(x)}cos(x)}=\frac{1}{sin(x)+\frac{cos^2(x)}{sin(x)}}$

we simply what we can:

$f(x)=\frac{1}{\frac{sin^2(x)+cos^2(x)}{sin(x)}}=sin(x)$

Thus, the correct answer is;

$f(x)=sin(x)$

6 0

1 year ago

Add and subtract rational numbers without common denominators. Show work! 1. 7/4 - 3/2 - 2/5 = 2. - 5/16 + 3/4 + 1/8 = 3. 3/4 -

alukav5142 [94]

$\dfrac{7}{4} - \dfrac{3}{2} - \dfrac{2}{5}$

$= \dfrac{7 \times 5}{4 \times 5} - \dfrac{3 \times 10}{2 \times 10} - \dfrac{2 \times 4}{5 \times 4}$

$= \dfrac{35}{20} - \dfrac{30}{20} - \dfrac{8}{20}$

$= \dfrac{35-30-8}{20}$

$= \dfrac{3}{20}$

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$-\dfrac{5}{16} + \dfrac{3}{4} + \dfrac{1}{8}$

$= -\dfrac{5}{16} + \dfrac{3 \times 4}{4 \times 4} + \dfrac{1 \times 2}{8 \times 2}$

$= -\dfrac{5}{16} + \dfrac{12}{16} + \dfrac{2}{16}$

$= \dfrac{-5+ 12 + 2}{16}$

$= \dfrac{9}{16}$

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$\dfrac{3}{4} - \dfrac{1}{3} - \dfrac{7}{12}$

$= \dfrac{3 \times 3}{4 \times 3} - \dfrac{1 \times 4}{3 \times 4} - \dfrac{7}{12}$

$= \dfrac{9}{12} - \dfrac{4}{12} - \dfrac{7}{12}$

$= \dfrac{9 - 4 - 7}{12}$

$= -\dfrac{2}{12}$

$= -\dfrac{1}{6}$

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$\dfrac{2}{9} - \dfrac{2}{12} - \dfrac{2}{3}$

$= \dfrac{2}{9} - \dfrac{1}{6} - \dfrac{2}{3}$

$= \dfrac{2 \times 2}{9 \times 2} - \dfrac{1 \times 3}{6 \times 3} - \dfrac{2 \times 6}{3 \times 6}$

$= \dfrac{4}{18} - \dfrac{3}{18} - \dfrac{12}{18}$

$= \dfrac{4 - 3 - 12}{18}$

$= - \dfrac{11}{18}$

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3 years ago