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Marysya12 [62]
3 years ago
12

Which role is responsible for turning the product backlog into incremental pieces of functionality? bookmark this question

Computers and Technology
2 answers:
STALIN [3.7K]3 years ago
7 0

The Development Team is responsible for turning the Product Backlog into incremental pieces of functionality.

Further Explanation:

The Product Backlog is an ordered list of all the things that have to be done in order to deliver a product. Depending on the nature of the product and the industry, this will include all kind of different work, but it is crucial to point out that it will include critical requirements, features and functions and non-critical work such as learning, experimentation, investigations into new practices and tools, etc. Scrum's Product Backlog is generally considered the most advanced agile project management backlog and teams that wish to have success with Scrum need to do  everything in their power to maintain a clear and efficient one.

Creation of Product Backlog

The Product Backlog usually starts off with only the most essential features and functionalities spelled out, possibly from a high-level road map of the product. As the team starts working on it, the Product Backlog evolves and is expanded with more details. The work that will be done in the upcoming Sprints is described in more detail than the work to be done later.

Under circumstances should the Product Backlog be re-prioritized

The Product Backlog should be re-prioritized constantly as the product evolves and new information is discovered. New business requirements, newly discovered dependencies and fluctuating market conditions are just some of the reasons for re-prioritizing the Product Backlog.

Product Owner’s Responsibility

The Product Owner is solely responsible for the Product Backlog. Only the Product Owner can add items to the backlog or remove them. They also have the final word on the ordering of the Product Backlog.  While the Product Owner is the person responsible for the Product Backlog, its refinement should be a collaborative effort where the rest of the Scrum Team contributes with its knowledge, insights and experience on the project so far.

Learn more:

  • When is implementation of a product backlog item considered complete?

        brainly.com/question/8526059

Keywords: product backlog, owner, scrum, re-prioritized, market

Misha Larkins [42]3 years ago
4 0
The answer is the team. Teams are self-establishing which no one not even the scrum master tells the team how to turn product backlog into augmentations of stoppable functionality. Each team member put on his or her knowledge to all of the complications. The interaction that outcomes progresses the entire scrum team’s general competence and usefulness. The optimal size for a scrum team is seven people, plus or minus two. When there are fewer than five team members, there is less interface and as a result less productivity improvement. The product owner and scrum master roles are not comprised in this count. Team arrangement may variation at the end of a sprint. Every time Team membership is altered, the productivity increased from self-organization is reduced.
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In this lab, you use the flowchart and pseudocode found in the figures below to add code to a partially created C++ program. Whe
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Answer:

The equivalent program in C++:

#include<iostream>

#include <sstream>

using namespace std;

int main(){

   string Score, Rank;

   cout<<"Enter student score and class rank: ";

   cin>>Score>>Rank;

   int testScore = 0, classRank = 0;

   stringstream sstream(Score);

   sstream>>testScore;

   

   stringstream tream(Rank);

   tream>>classRank;

   

   if (testScore >= 90){

       if(classRank >=25){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else if(testScore >= 80){

       if(classRank >=50){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else if(testScore >= 70){

       if(classRank >=75){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else{cout<<"Reject";}

   return 0;

}

Explanation:

This declares Score and Rank as string variables

   string Score, Rank;

This prompts the user for score and class rank

   cout<<"Enter student score and class rank: ";

This gets the user input

   cin>>Score>>Rank;

This declarees testScore and classRank as integer; and also initializes them to 0

   int testScore = 0, classRank = 0;

The following converts string Score to integer testScore

<em>    stringstream sstream(Score);</em>

<em>    sstream>>testScore;</em>

The following converts string Rank to integer classRank

   stringstream tream(Rank);

   tream>>classRank;

The following conditions implement the conditions as given in the question.    

If testScore >= 90

<em>    if (testScore >= 90){</em>

If classRank >=25

<em>        if(classRank >=25){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    } ---</em>

If testScore >= 80

<em>    else if(testScore >= 80){</em>

If classRank >=50

<em>        if(classRank >=50){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    }</em>

If testScore >= 70

<em>    else if(testScore >= 70){</em>

If classRank >=75

<em>        if(classRank >=75){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    }</em>

For testScore less than 70

<em>    else{cout<<"Reject";}</em>

<em />

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Explanation:

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The following SQL statement uses a(n) _____. SELECT P_CODE, P_DESCRIPT, P_PRICE, V_NAME FROM PRODUCT, VENDOR WHERE PRODUCT.V_COD
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Answer:

The answer is c. “old-style” join.

Explanation:

SELECT P_CODE, P_DESCRIPT, P_PRICE, V_NAME

FROM PRODUCT, VENDOR

WHERE PRODUCT.V_CODE = VENDOR.V_CODE;

The SELECT clause represents all the columns to be displayed.

The FROM clause represents the tables which are used to extract the columns.

The WHERE clause shows the common column that exists in both the tables. This represents the old-style join when JOIN keyword was not used.

The tables are joined in two ways.

1. Using JOIN keyword

The syntax for this is given as

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Two tables are taken at a time when JOIN keyword is used.

If more tables are to be used, they are mentioned as follows.

SELECT column1, column2

FROM table1 JOIN table2

ON table1.column3 = table2.column3

JOIN table3

ON table3.column4 = table1.column4

( ON table3.column5 = table2.column5 )  

The part in italics shows that the third table can either share the same column with table1 or table2.

The given query can be re-written using JOIN as shown.

SELECT P_CODE, P_DESCRIPT, P_PRICE, V_NAME

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2. Equating common column in WHERE clause

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FROM table1, table2

WHERE table1.column3 = table2.column3;

This returns all rows from two tables having the same value of the common column.

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Tables to be used are mentioned in FROM clause separated by commas.

Tables are joined based on the same column having same values.

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