2006 is the answer and the boston red sox were the first team to win 5 chamships
Answer:
To solve the problem, first,
a) The computer account should be reset.
b) Deactivate the computer from the domain.
c) Then, rejoin it to the domain.
Explanation:
A domain is a network that allows different computers to function and operate from a common server. A domain may or may not be protected by a password. Setting up a domain provides additional security thereby blocking other computer networks from having access to it. When a person is experiencing difficulties in logging into a domain, there are certain things to be done to resolve the issue.
First, reset the computer account.
Secondly, deactivate the computer from the domain.
Third, Rejoin it back to the domain.
Answer:
Explanation:
1 : Ctrl + X
2 Ctrl + C
3 Ctrl + L
4 Ctrl + V
5 Ctrl + B
6 Ctrl + R
7 Ctrl + I
8 Ctrl + E
9 Ctrl + U
10 Ctrl + Z
11 Ctrl + Y
12 Ctrl + N
End
13 Ctrl + A
Home
14 Ctrl + J
15 Ctrl + 2
16 Ctrl + S
17 Ctrl + 1
18 F12
19 Ctrl + W
-----------
20 Ctrl + K
21 Ctrl + ]
22 Ctrl + (left arrow)
23 Ctrl + (right arrow)
24 Ctrl + [
25 Ctrl + Del
26 Ctrl + 5
27 F1 pls mark me as brainliest and
check all the short cuts
Answer: True
Explanation: For loop is used in the C++ programming is defined as the statement that defines about the flow control .This loop works under some condition that is considered.
For loop is evaluated to execute for one time if the statement condition is true but there are also chances of no execution at all because of the incorrect condition. So, for loop might not run even once in that condition.Thus , the statement given is true.
Answer:
Sequence of popped values: h,s,f.
State of stack (from top to bottom): m, d
Explanation:
Assuming that stack is initially empty. Suppose that p contains the popped values. The state of the stack is where the top and bottom are pointing to in the stack. The top of the stack is that end of the stack where the new value is entered and existing values is removed. The sequence works as following:
push(d) -> enters d to the Stack
Stack:
d ->top
push(h) -> enters h to the Stack
Stack:
h ->top
d ->bottom
pop() -> removes h from the Stack:
Stack:
d ->top
p: Suppose p contains popped values so first popped value entered to p is h
p = h
push(f) -> enters f to the Stack
Stack:
f ->top
d ->bottom
push(s) -> enters s to the Stack
Stack:
s ->top
f
d ->bottom
pop() -> removes s from the Stack:
Stack:
f ->top
d -> bottom
p = h, s
pop() -> removes f from the Stack:
Stack:
d ->top
p = h, s, f
push(m) -> enters m to the Stack:
Stack:
m ->top
d ->bottom
So looking at p the sequence of popped values is:
h, s, f
the final state of the stack:
m, d
end that is the top of the stack:
m