Average of 45 and 38

When one company is hired to design, construct, and test a production facility for a client, the arrangement is called ________.

svlad2 [7]

Answer:

The answer is: "Key in hand" or "Turnkey contract".

Step-by-step explanation:

These are the names that receive the type of projects in which the builder assumes the execution of the work as a whole, from the phase of basic engineering, detail, management of purchases and subcontracts, purchase of materials and equipment to the supervision of the Work and setup. The client receives the facility ready to be used, just as when you buy a new car and you receive the key to take it out from the dealership.

8 0

4 years ago

6) Add or subtract: a) (4x® - 5x + 15) - (11 - 7x - 2x) b)(9x- 6x® - 7x-2) + (10x - 8x + 11)

Marat540 [252]

Answer:

a) (4x® - 5x + 15) - (11 - 7x - 2x)

b)(9x- 6x® - 7x-2) + (10x - 8x + 11)

Step-by-step explanation:

a) (4x® - 5x + 15) - (11 - 7x - 2x)

b)(9x- 6x® - 7x-2) + (10x - 8x + 11)

6 0

3 years ago

Consider two circular swimming pools. Pool A has a radius of 16 feet, and Pool B has a diameter of 9.94 meters. Complete the des

Dmitry_Shevchenko [17]

Answer:

Pool B has the greater circumference.

Step-by-step explanation:

Pool A has a radius of 16 feet, and Pool B has a diameter of 9.94 meters.

We want to see which pool has a greater circumference.

The circumference of a circle is the distance around a circle or the total length of a circle, and it is given as:

$C = 2\pi r$

where r = radius of the circle

So that our comparison can be accurate, let us put the dimensions of both pools in a single unit, metre.

The radius of pool A is 16 feet.

1 foot = 0.305 metres

16 feet = 4.88 metres

The radius of pool A in metres is 4.88 metres

CIRCUMFERENCE OF POOL A

$C = 2 * \pi * 4.88 = 30.66 m$

CIRCUMFERENCE OF POOL B

$C = 2 * \pi * 9.94 = 62.45 m$

As we can see, pool B has the greater circumference.

3 0

3 years ago

TRIANGLE ABC IS DILATED BY A SCALE FACTOR OF 0.5 WITH THE ORIGIN AS THE CENTER OF DILATION, RESULTING IN THE IMAGE TRIANGLE A'B'

const2013 [10]

Answer: The length of the line B'C" is 1 unit.

Step-by-step explanation:

Given: Triangle ABC is dilated by a scale factor of 0.5 with the origin as the center of dilation , resulting in the image Triangle A'B'C'.

If A (2,2), B= (4,3) and C=(6,3).

Distance between (a,b) and (c,d): $D=\sqrt{(d-b)^2+(c-b)^2}$

Then, BC $=\sqrt{(3-3)^2+(6-4)^2}$

$\\\\=\sqrt{0+2^2}\\\\=\sqrt{4}\\\\=2\text{ units}$

Length of image = scale factor x length in original figure

B'C' = 0.5 × BC

= 0.5 × 2

= 1 unit

Hence, the length of the line B'C" is 1 unit.

5 0

3 years ago

Given B is the midpoint of AC, what is AC ? A. 54 B. 27 C. 6 D. 18

lubasha [3.4K]

A. 54

The fact that B is the midpoint means that AB = BC so you can set up the equation of
4x+3 = 3x+9

Then solve for x by subtracting 3 from the left and 3x from the right to get

X=6

Finally, plug that back in to your line and solve for the total value

4(6) + 3 + 3(6) +9 = 54

6 0

3 years ago