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3 years ago

The minimum number of triangles needed to construct a polygon is 4. Which is the name of the polygon?

Mathematics

2 answers:

Snezhnost [94]3 years ago

7 0

Answer:

Option B. Hexagon

Step-by-step explanation:

The minimum number of triangles needed to construct a polygon is always represented by (n - 2) where n is the number of sides.

Now we put the values of n.

for n = 3 number of triangles = (3 - 2) = 1

for n = 4 number of triangles = (4 - 2) = 2

for n = 5 number of triangles = (5 - 2) = 3

for n = 6 number of triangles = (6 - 2) = 4

We have got the answer.

If minimum number of triangles are 4 then polygon formed is Hexagon where number of sides n = 6.

Option B. Hexagon is the answer.

inysia [295]3 years ago

4 0

A polygon has 5 or more sides and is made of 4 triangles your asking for the name of it which is confusing because then you list a 8,6,7 and 4 sided shapes can you explain that? so it could be A,B, or C but only one you can make in to 4 triangle so i would go with B

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Consider the given data. x 0 2 4 6 9 11 12 15 17 19 y 5 6 7 6 9 8 8 10 12 12 Use the least-squares regression to fit a straight

levacccp [35]

Answer:

See below

Step-by-step explanation:

By using the table 1 attached (See Table 1 attached)

We can perform all the calculations to express both, y as a function of x or x as a function of y.

Let's make first the line relating y as a function of x.

y as a function of x

(y=response variable, x=explanatory variable)

$\bf y=m_{yx}x+b_{yx}$

where

$\bf m_{yx}$ is the slope of the line

$\bf b_{yx}$ is the y-intercept

In this case we use these formulas:

$\bf m_{yx}=\frac{(\sum y)(\sum x)^2-(\sum x)(\sum xy)}{n\sum x^2-(\sum x)^2}$

$\bf b_{yx}=\frac{n\sum xy-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}$

n = 10 is the number of observations taken (pairs x,y)

Note: Be careful not to confuse

$\bf \sum x^2$ with $\bf (\sum x)^2$

Performing our calculations we get:

$\bf m_{yx}=\frac{(83)(95)^2-(95)(923)}{10*1277-(95)^2}=176.6061$

$\bf b_{yx}=\frac{10*923-(95)(83)}{10(1277)-(95)^2}=0.3591$

So the equation of the line that relates y as a function of x is

In order to compute the standard error $\bf S_{yx}$ , we must use Table 2 (See Table 2 attached) and use the definition

$\bf s_{yx}=\sqrt{\frac{(y-y_{est})^2}{n}}$

and we have that standard error when y is a function of x is

$\bf s_{yx}=\sqrt{\frac{39515985}{10}}=1987.8628$

Now, to find the line that relates x as a function of y, we simply switch the roles of x and y in the formulas.

So now we have:

x as a function of y

(x=response variable, y=explanatory variable)

$\bf x=m_{xy}y+b_{xy}$

where

$\bf m_{xy}$ is the slope of the line

$\bf b_{xy}$ is the x-intercept

In this case we use these formulas:

$\bf m_{xy}=\frac{(\sum x)(\sum y)^2-(\sum y)(\sum xy)}{n\sum y^2-(\sum y)^2}$

$\bf b_{xy}=\frac{n\sum xy-(\sum x)(\sum y)}{n(\sum y^2)-(\sum y)^2}$

n = 10 is the number of observations taken (pairs x,y)

Note: Be careful not to confuse

$\bf \sum y^2$ with $\bf (\sum y)^2$

Remark: If you wanted to draw this line in the classical style (the independent variable on the horizontal axis), you would have to swap the axis X and Y)

Computing our values, we get

$\bf m_{xy}=\frac{(95)(83)^2-(83)(923)}{10*743-(83)^2}=1068.1072$

$\bf b_{xy}=\frac{10*923-(95)(83)}{10(743)-(83)^2}=2.4861$

and the line that relates x as a function of y is

To find the standard error $\bf S_{xy}$ we use Table 3 (See Table 3 attached) and the formula

$\bf s_{xy}=\sqrt{\frac{(x-x_{est})^2}{n}}$

and we have that standard error when y is a function of x is

$\bf s_{xy}=\sqrt{\frac{846507757}{10}}=9200.5856$

In both cases the correlation coefficient r is the same and it can be computed with the formula:

$\bf r=\frac{\sum xy}{\sqrt{(\sum x^2)(\sum y^2)}}$

Remark: This formula for r is only true if we assume the correlation is linear. The formula does not hold for other kind of correlations like parabolic, exponential,..., etc.

Computing the correlation coefficient :

$\bf r=\frac{923}{\sqrt{(1277)(743)}}=0.9478$

5 0

4 years ago

the melting point of mercury is -39°C. the freezing point of alcohol is 114°C. How much cooker is the melting point of mercury t

8_murik_8 [283]

This is one of those cases where you have to believe that a minus times a minus is a plus.

114 - - 39 = 153 degrees. The freezing of mercury is 153 degrees cooler than the freezing point of alcohol. I would check your descriptions. Did you mean boiling point of Alcohol?

8 0

4 years ago

Which two temperatures have a sum of 0 degrees Celsius?

lidiya [134]

−2 degrees Celsius and −2 degrees Celsius and 2 degrees Celsius and 2 degrees Celsius

8 0

3 years ago

Read 2 more answers

PLEASE HELP ON MULTIPLE CHOICE MATH QUESTION

kotegsom [21]

I believe the answer you are looking for is the third option

6 0

3 years ago

Can you guys help me please :(

ale4655 [162]

Answer:

720 m²

Step-by-step explanation:

Area = base × height

= 12 × 6

= 72 mm²

≈ 720 m² (1 mm = 10 m)

5 0

2 years ago