Question

1) The Sun has an average surface temperature of approximately 6000 K. Calculate the power per unit area released by the surface of the Sun using Stefan-Boltzmann Law and report the value below. Units are a must. (2 points)
Power per unit area released by the Sun=

Answer 1

Answer:

Power per unit area released by the Sun is 73,488,384 Watt per meter square.

Explanation:

The Sun has an average surface temperature of approximately,T= 6000 K

The power per unit area released by the surface of the Sun be P'

Stefan-Boltzmann Law  is given as:

$P'=\frac{Power}{Area}=\sigma T^4$

where

$\sigma =5.6704\times 10^{-8} Watt/m^2K^4$ Stefan-Boltzmann constant

T = Absolute temperature of the body

Power per unit area released by the Sun:

$=5.6704\times 10^{-8} Watt/m^2K^4\times (6000 K)^4=73,488,384 Watt/m^2$