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Kazeer [188]
3 years ago
7

Trying to help my bro solve this Y= -2x+2

Mathematics
2 answers:
lesya [120]3 years ago
6 0
The slope-intercept form is <span><span>y=mx+b</span><span>y=mx+b</span></span>, where <span>mm</span> is the slope and <span>bb</span> is the y-intercept.<span><span>y=mx+b</span><span>y=mx+b</span></span>Find the values of <span>mm</span> and <span>bb</span> using the form <span><span>y=mx+b</span><span>y=mx+b</span></span>.<span><span>m=2</span><span>m=2</span></span><span><span>b=2</span><span>b=2</span></span>The slope of the line is the value of <span>mm</span>, and the y-intercept is the value of <span>bb</span>.Slope: <span>22</span>Y-Intercept: <span>2</span>
Alexus [3.1K]3 years ago
3 0
Are you trying to graph it because it is in y=mx+b form.

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What is the answer to <br>11-9m=-70
Fynjy0 [20]

Answer:

m=9

Step-by-step explanation:

11-9m=-70

-11        -11

-9m  =  -81

divide both sides by -9 and you get m=9

7 0
3 years ago
Read 2 more answers
Solve 2,401 = 76 – 2x.
Oduvanchick [21]
Subtract 76 on both sides:

2401 - 76 = 76 - 2x - 76 

2325 = -2x

Divide both sides by -2:

-1162.5 = x
4 0
3 years ago
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If the diagonals of a parallelogram are equal, then show that it is a rectangle.
Harlamova29_29 [7]

Answer:

Given: In parallelogram ABCD, AC=BD

To prove : Parallelogram ABCD  is rectangle.

Proof : in △ACB and △BDA

AC=BD  ∣ Given

AB=BA ∣ Common

BC=AD ∣ Opposite sides of the parallelogram ABCD

△ACB ≅△BDA∣SSS Rule

∴∠ABC=∠BAD...(1) CPCT

Again AD ∥ ∣ Opposite sides of parallelogram ABCD

AD ∥BC and the traversal AB intersects them.

∴∠BAD+∠ABC=180∘ ...(2) _ Sum of consecutive interior angles on the same side of the transversal is 

180∘

From (1) and (2) ,

∠BAD=∠ABC=90∘

∴∠A=90∘ and ∠C=90∘

Parallelogram ABCD is a rectangle.

4 0
2 years ago
What is the square root of 75m
umka2103 [35]

Answer:

the square root of 75 is either \sqrt75 or 8.66

Step-by-step explanation:

6 0
3 years ago
How to factor 1-49c^2
Dima020 [189]
Ok so this is a difference of 2 perfect squares
1=1^2
49c^2=(7c)^2
to factor you remember
a^2-b^2=(a+b)(a-b) so

1^2-(7c)^2=(1+7c)(1-7c)
5 0
3 years ago
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