Answer:
#1) y = -4x + 1; #2) parallel; #3) y = -1/2x + 5/2; #4) y = 2x + 4; #5) Never
Step-by-step explanation:
#1) We want a line that passes through (1, -3) and is parallel to y = 2-4(x-1). First we simplify our equation using the distributive property:
y = 2-4(x-1) = 2-4(x) -4(-1) = 2-4x--4 = 2-4x + 4 = -4x + 6
Lines that are parallel have the same slope; this means we want a line through (1, -3) with a slope of -4. Using point-slope form,
![y-y_1=m(x-x_1)\\\\y--3=-4(x-1)\\\\y+3=-4(x)-4(-1)\\\\y+3=-4x+4\\\\y+3-3=-4x+4-3\\\\y=-4x+1](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29%5C%5C%5C%5Cy--3%3D-4%28x-1%29%5C%5C%5C%5Cy%2B3%3D-4%28x%29-4%28-1%29%5C%5C%5C%5Cy%2B3%3D-4x%2B4%5C%5C%5C%5Cy%2B3-3%3D-4x%2B4-3%5C%5C%5C%5Cy%3D-4x%2B1)
#2) We must first write our second equation in slope-intercept form by isolating the y term:
2x+y=7
Subtract 2x from each side"
2x+y-2x = 7-2x
y = -2x+7
This means the slope is -2; the slopes are the same, so the lines are parallel.
#3) The slope of our given equation is 2. To be perpendicular, the second line must have a slope that is a negative reciprocal (flipped and opposite signs); this makes it -1/2. Using point-slope form,
![y-0=\frac{-1}{2}(x-5)\\\\y=\frac{-1}{2}(x)+\frac{-1}{2}(-5)\\\\y=\frac{-1}{2}x+\frac{5}{2}](https://tex.z-dn.net/?f=y-0%3D%5Cfrac%7B-1%7D%7B2%7D%28x-5%29%5C%5C%5C%5Cy%3D%5Cfrac%7B-1%7D%7B2%7D%28x%29%2B%5Cfrac%7B-1%7D%7B2%7D%28-5%29%5C%5C%5C%5Cy%3D%5Cfrac%7B-1%7D%7B2%7Dx%2B%5Cfrac%7B5%7D%7B2%7D)
#4) The slope of Main Street on the diagram, found by using rise/run, is 2. This means the bike path will also have a slope of 2 in order to be parallel. The park entrance is at (0, 4). This makes the equation y = 2x+4.
#5) Two lines with the same slope are always parallel. They are never perpendicular.