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defon
3 years ago
11

Solve 3x+2y=4 4x+3y=7 algebraically

Mathematics
1 answer:
Leona [35]3 years ago
8 0
Step 1. Multiply first equation with -3 and the second one with 2. You'll get:
\left \{ {{-9x-6y=-12} \atop {8x+6y=14}} \right.

Step 2. Add both equations together. You'll get:
-x=2, which gives x = -2

Step 3. Replace x = -2 in the first equation and calculate y.
3(-2)+2y=4\\
y=\frac{4+6}{2}=5

The solution is: x=-2, y=5
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\bf \textit{circumference of a circle}\\\\
C=2\pi r\qquad r=radius=\frac{diameter}{2}\\\\
-----------------------------\\\\

\begin{array}{lcccclllll}
&radius&\$&Cmfc&\frac{Cmfc}{\$}\\
&---&---&-----&-----\\
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\end{array}

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and "edge per dollar" simply means, how much circumference per dollar
or \bf \cfrac{Cmfc}{\$}

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