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Elodia [21]
3 years ago
7

A large field measures 70 feet by 525 feet. If you divide it up into equal square garden plots, what size would the largest poss

ible plot be with sides of whole number length?​
Mathematics
1 answer:
fenix001 [56]3 years ago
7 0

9514 1404 393

Answer:

  35 feet square

Step-by-step explanation:

The greatest common factor of 70 and 525 is 35. The largest square plot can be 35 feet on a side.

  70 = 2·35

  525 = 15·35

__

I like to find the GCD (greatest common divisor) using Euclid's algorithm. We find the remainder when dividing the larger by the smaller. When that remainder is not zero, we replace the larger number with the remainder, and repeat. When the remainder is zero, the divisor is the GCD.

  525/70 = 7 r 35

  70/35 = 2 r 0 . . . . . 35 is the GCD

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10 coupons are given to 20 shoppers in a store. Each shopper can receive at most one coupon. 5 of the shoppers are women and 15
zmey [24]

Answer:

\, {20 \choose 10} - {15 \choose 10}

Step-by-step explanation:

We can find the total amount of ways at least a woman receives a coupon by calculating the total amount of possibilities ot distribute the coupon and substract it to the total amount of possibilities to distribute 10 coupons to the 15 men (this is the complementary case that at least a woman receives a cupon).

- The total amount of possibilities to distribute the coupons among the 20 shoppers is equivalent to the total amount of ways to pick a subset of 10 elements from a set of 20. This is the combinatiorial number of 20 with 10, in other words, \, {20 \choose 10} = \frac{20!}{10!10!} .

- To calculate the total amount of possibilities to distribute the coupons among the 15 men, we need to make the same computation we made above but with a set of 15 elements instead of 20. This gives us  \, {15 \choose 10} = \frac{15!}{10!5!} possibilities.

Therefore, we have \, {20 \choose 10} - {15 \choose 10} possibilities to distribute the coupons so that at least one woman receives a coupon.

I hope that works for you!

3 0
3 years ago
Solve for x: 1 1/5 x -2 1/3 < 1/7 x+ 1 1/2
Firlakuza [10]
Solving inequalities is similar to solving a regular equation. The only thing you need to worry about with inequalities is that when you are dividing or multiplying by a negative number, you must flip the inequality sign. You won't have to worry about that here if the coefficient in front of x is positive when you divide!

Also remember:
- To add/subtract fractions, you have to turn all mixed numbers into improper fractions (if needed), <span>find a common denominator on both fractions (if needed), add/subtract the numerators, put the sum/difference over the common denominator, and simplify if needed. 

- To multiply fractions, multiply the numerators and multiply the denominators. Put the product of the numerators over the product of the denominators.

- To divide fractions, remember that dividing by a fraction is the same as multiplying by the inverse of that fraction (aka fraction flipped). 

- To turn mixed numbers into improper fractions, multiply the whole number by the denominator of the fraction. Add the numerator of the fraction to the product you get, and put that final sum over the original denominator.

Back to the problem:
</span>You are told that 1 \frac{1}{5} x - 2 \frac{1}{3} \ \textless \ \frac{1}{7} x + 1 \frac{1}{2} and you have to solve for x.
<span>
1) </span>Using the info for converting mixed numbers to improper fractions from above, you know that 1 \frac{1}{2} =  \frac{3}{2} and 2 \frac{1}{3} =  \frac{7}{3} and 1 \frac{1}{5} x =  \frac{6}{5} x. Now add/subtract using the info above, isolating the variable x by adding 2 \frac{1}{3} to both sides and subtracting \frac{1}{7} x from both sides. 
1 \frac{1}{5} x - 2 \frac{1}{3} \ \textless \ \frac{1}{7} x + 1 \frac{1}{2}\\&#10;\frac{6}{5} x -  \frac{7}{3} \ \textless \ \frac{1}{7} x + \frac{3}{2}\\&#10;(\frac{6}{5} x  - \frac{1}{7} x) \ \textless \ (\frac{3}{2} + \frac{7}{3})\\&#10;(\frac{42}{35} x  - \frac{5}{35} x) \ \textless \ (\frac{9}{6} + \frac{14}{6})\\&#10; \frac{37}{35} x \ \textless \   \frac{23}{6}

2) Divide both sides by \frac{37}{35} to get the inequality for x. Remember the info for dividing from above:
\frac{37}{35} x \ \textless \ \frac{23}{6}\\&#10;x \ \textless \  \frac{23}{6} \div \frac{37}{35}  \\&#10;x \ \textless \  \frac{23}{6} \times \frac{35}{37} \\&#10;x \ \textless \  \frac{805}{222}

Your final answer is x < \frac{805}{222} or x < 3 \frac{139}{222}.
3 0
3 years ago
PLEASE HELP ME!!! I NEED THIS REALLY SOON OR I WILL FAIL! What are some measurements that might be easier if we worked in the me
inessss [21]

Answer:

Centimeters might be easier because they can be much more precise than inches when there isn't an ideal length. Kilometers might be easier because it would not require such large numbers to work with.

Step-by-step explanation:

:)

5 0
3 years ago
Number 6 part a &amp; b<br> Number 7<br> Please &amp; thank you
miv72 [106K]

Answer:

6- Part A: 750a+1200r=1000000

    Part B: 1065a+876r=1000000

Solution of the system: a\approx521.739\;\;\;\;b\approx507.246

Step-by-step explanation:

<u>Part A:</u>

In words, the equation is formed like this:

Total kg of Arabica + Total kg of Robusta = Total kg of coffee

Now, the total of each yield is calculated by the product of kg/hectare and number of hectares. Thus, the equation is:

750a+1200r=1000000

<u>Part B:</u>

In words:

Arabica's worth + Robusta's worth  = plantation worth

Each yield's worth is given by the product of the price per kg and the corresponding production. So, the equation is:

1.42(750a)+0.73(1200r)=1000000\\1065a+876r=1000000

3 0
3 years ago
Michelle purchased a kids table with a square top if the area of the square top is 400 square inches what is the length of one o
worty [1.4K]

400 in² = (20 in)²

The area of a square is the square of the side length.

The length of one of the sides is 20 inches.

7 0
3 years ago
Read 2 more answers
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