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Nat2105 [25]
4 years ago
5

Consider the piecewise-defined function.

Mathematics
2 answers:
Dmitry_Shevchenko [17]4 years ago
6 0

Answer:

B 12

Step-by-step explanation:

Since f(6)  means we want to evaluate the function when x=6

We will want to use f(x) =2x  because  5<= 6 <10

f(6) = 2*6

f(6)=12

Setler79 [48]4 years ago
4 0

f(x) = x   when 2 ≤ x < 5

So you can use this function if "x" is greater than or equal to 2 and less than 5


f(x) = 2x   when 5 ≤ x < 10

You can use this function if "x" is greater than or equal to 5 and less than 10



f(6) This means that x is 6, so you can plug in 6 for "x" in the equation.

You use the second function because 6 is greater than 5 and less than 10


f(x) = 2x

f(6) = 2(6)

f(6) = 12     Your answer is B

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Solve the equation for P: 3k=7Q+6p
iren [92.7K]

3k=7Q+6p

Solve for P which means we have to make 'p' alone

3k=7Q+6p\\\\ Add  7Q on both sides \\\\ 3k - 7Q = 7Q - 7Q + 6p\\\\ \left ( 3k - 7Q \right ) = 6p\\\\ Divide both side by 6 to make p alone \\\\ \frac{\left ( 3k - 7Q  \right )}{6} = \frac{6p}{6}\\\\ p = \frac{\left ( 3k - 7Q  \right )}{6}

7 0
3 years ago
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Help will give braniest answer to person who is correct find the degree measure of each angle in the triangle
Irina-Kira [14]

Answer:

Angle I = 90 degrees

Angle J = 61 degrees

Angle K = 29 degrees

Step-by-step explanation:

Angle I is given

We know that the angles in all triangles add up to 180. Since we are given that angle I is equal to 90 degrees, we now know that angle J + angle K = 90 degrees:

(5x+26) + (2x+15) = 90

Solve for X:

7x + 41 = 90

7x = 49

x = 7

Angle J =  (5x + 26) = (5(7) + 26) = 61

Angle K = (2x + 15) = (2(7) + 15) = 29

Checking your work: 61 + 29 = 90

5 0
3 years ago
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In trapezoid ABCD, AB ∥ CD , m∠A=90°, AD=8 in, DC=9 in, CB=10 in, and ∠B is acute. Find DB.
kiruha [24]

Answer:

the length of DB is 17 in

Step-by-step explanation:

Consider the sketch attached.

We will draw an imaginary line from point C to met line AB at point E.

A right-angled triangle will now be formed between points CBE.

The dimensions of the right-angled triangle will be:

CB = 10 in

CE= 8 in

EB = unknown

We will now proceed to find out the length of side EB using the Pythagoras' theorem.

EB =\sqrt{CB^2 -CE^2} \\EB =\sqrt{10^2 -8^2} \\EB = 6 in

From the shape, we can find out that another right-angled triangle is made between points DAB.

The dimensions of the triangle are:

DA= 8in

AB = 9 in + 6 in = 15 in

DB = unknown.

We will now proceed to find out the length of side DB using the Pythagoras' theorem.

DB =\sqrt{AD^2 +AB^2} \\DB =\sqrt{8^2 +15^2} \\DB = 17 in

Therefore, the length of DB is 17 in

6 0
4 years ago
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Someone pls help its important
UkoKoshka [18]

Answer:

  1. the y-intercept is (0,5)
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Step-by-step explanation:

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3 years ago
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Please help with these 2 problems
HACTEHA [7]

(\frac{16}{9})^{\frac{2}{3} }. (\frac{4}{3} ) ^{\frac{5}{3} } = \frac{16}{9}

4ˣ⁻¹ = 49 / 4

<h3>How to simplify an expression?</h3>

The expressions can be simplified as follows;

(\frac{16}{9})^{\frac{2}{3} }. (\frac{4}{3} ) ^{\frac{5}{3} }

Hence,

(\frac{16}{9})^{\frac{2}{3} }. (\frac{4}{3} ) ^{\frac{5}{3} } = (\frac{4}{3} )^{2(\frac{2}{3} )}.(\frac{4}{3} ) ^{\frac{5}{3} }

Therefore,

(\frac{4}{3} )^{2(\frac{2}{3} )}.(\frac{4}{3} ) ^{\frac{5}{3} } = (\frac{4}{3} )^{\frac{4}{3} } .(\frac{4}{3} )^{\frac{5}{3} }

Finally,

(\frac{4}{3} )^{\frac{4}{3} } .(\frac{4}{3} )^{\frac{5}{3} } = (\frac{4}{3} )^{3}

(\frac{4}{3} )^{3} = \frac{16}{9}

2ˣ = 7

4ˣ⁻¹ = 2²⁽ˣ⁻¹⁾ = 2²ˣ ⁻ ²  = 2²ˣ / 2² = (2ˣ)² / 2²

Therefore,

(2ˣ)² / 2² = 7² / 2² = 49 / 4

Hence,

4ˣ⁻¹ = 49 / 4

Finally, the  (\frac{16}{9})^{\frac{2}{3} }. (\frac{4}{3} ) ^{\frac{5}{3} } is equal to \frac{16}{9}  and for the second part  4ˣ⁻¹ = 49 / 4

learn more on simplification here: brainly.com/question/17513857

#SPJ1

4 0
2 years ago
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