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3 years ago

Is |4x+2|+6=0 no solution, all real numbers, 0, and 2

1 answer:

7 0

|4x + 2| + 6 = 0

Subtract 6 from each side: |4x + 2| = -6

But the absolute value of a number is always positive.
No value of 'x' can ever make |4x + 2| negative.

So the equation has no solution.

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Please help me solve this

uysha [10]

Answer:

(D) (a + 4)/2

Step-by-step explanation:

To solve, you need to subtract the first equation from the second.

9p = 3a + 1

- 7p = 2a - 3

2p = 1a + 4

Now, you need to rearrange the equation so that is equal to p.

2p = a + 4

(2p)/2 = (a + 4)/2

p = (a + 4)/2

This gives you answer choice D.

5 0

2 years ago

Mike earned $11.76 per hour for working 23.5 hours last week. how much money did mike earn last week?

densk [106]

Just multiply.

11.76 * 23.5= 276.36

So Mike earned $276.36 last week

6 0

2 years ago

Factor completely. 3h^4+24h^3+21h^2. BRAINLIST PLEASE HELP FAST!!!

mote1985 [20]

3h2 • (h + 7) • (h + 1) is the simplified version.

3 0

2 years ago

Match each power of a power expression with its simplified expression.

VARVARA [1.3K]

Answer:

> $(4^6)^{-3}$ = $\frac{1}{4 ^ {18}}$

> $(4^{-3})^{-3}$ = $4 ^ 9$

> $(4^0)^{-9}$ = $4 ^0$

> $(-4^{-9})^2$ = $(-4) ^ {-18}$

Step-by-step explanation:

We have to expand the powers of each of them:

> $(4^6)^{-3}$ = $4^{(6 * -3)}$

= $4 ^ {-18}$

$(4^6)^{-3}$ = $\frac{1}{4 ^ {18}}$

> $(4^{-3})^{-3}$ = $4 ^ {(-3 * -3)}$

$(4^{-3})^{-3}$ = $4 ^ 9$

> $(4^0)^{-9}$ = $4 ^ {(0 * -9)}$

$(4^0)^{-9}$ = $4 ^0$

> $(-4^{-9})^2$ = $-4 ^ {( -9 * 2)}$

$(-4^{-9})^2$ = $-4 ^ {-18}$

8 0

2 years ago

Read 2 more answers

I need help on my corrections! Can someone help me please if u do know!!

Harlamova29_29 [7]

Looks good for high school math make sure the teacher sees you're work clearly and know what the numbers are overall you should be good

8 0

3 years ago