1 answer:
<h2>Answer:</h2><h2>2(x^2 + 2x + 3) or 
.</h2><h2>~</h2><h3>To find the answer, simply factor 2 out of 2x^2+4x+6 to get your final answer, </h3><h3>2(x^2 + 2x + 3)</h3><h2>~</h2><h3>Thank you for taking the time to read this!</h3><h3><u>And I hope you have a good day, Loves!</u></h3><h3><em><u>Also if I'm right can you let me know, please?</u></em></h3>
<em><u>Also Also if I am right can I please have Brainliest??</u></em>
<u>You don't need to, I'm just glad I could help. ^^</u>
(If I did help-)
And don't forget to eat a full meal, and have at least one cup of water today!
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Answer:
and
.
Step-by-step explanation:
So I believe the problem is this:
where we are asked to find values for and
such that the equation holds for any
in the equation's domain.
So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).
In other words this will clear the fractions.
As you can see there was some cancellation.
I'm going to plug in -7 for x because x+7 becomes 0 then.
Divide both sides by -10:
Now we have:
with
I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.
Divide both sides by 10:
So and
.