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zhenek [66]
3 years ago
12

A major stadium has 45,000 seats. If baseball fans have bought 4/5 seats for the next game, how many seats available?

Mathematics
1 answer:
erastova [34]3 years ago
4 0
36,000 seats would be available! 
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Which equation could represent each graphed polynomial function <br><br> PLEASE HELP FAST!!!
Ket [755]

Answer:

y = x⁴- 5x² + 4

y = x(x + 3)(x - 2)

Step-by-step explanation:

1). y = x⁴- 5x² + 4

      = x⁴- 4x² - x² + 4

      = x²(x² - 4) - 1(x²- 4)

   y = (x² - 1)(x² - 4)

   y = (x - 1)(x + 1)(x - 2)(x + 2)

  Therefore, zeros of this polynomial are,

   x = -2, -1, 1, 2

   From the given graphs, first graph has the zeros (x-intercepts) as x = -2, -1, 1, 2.

   So the graph (1) represents the polynomial → y = x⁴- 5x² + 4

2). Second graph shows the x-intercepts at x = -3, 0, 2

   Since, y = x(x + 3)(x - 2) is the polynomial with x intercepts at x = -3, 0, 2

   Therefore, y = x(x + 3)(x - 2) represents the second graph.

4 0
3 years ago
Show that f '(x) = g'(x) for all x in their domains. Can we conclude from the corollary below that f − g is constant? If f '(x)
spayn [35]

Answer:

Answer: 15 cm

Step-by-step explanation:

7 0
3 years ago
What is the area of a circle with a circumference of 2 Pi
maria [59]
The answer will just be pi
7 0
3 years ago
According to Reuters, a survey undertaken by the National Center for Health Statistics revealed that about 25% of U.S. household
ddd [48]

Answer:

a) P=0.8

b) P=0.67

c) P=0.05

d) P=0.33

e) P=0.45

Step-by-step explanation:

a. What is the probability that the household has only a cell phone and has high-speed Internet?

This probability is stated in the question: "Suppose of U.S. households having only a cell phone, 80% have high-speed Internet", so the probability is P=0.8.

P(C\&I)=0.8

b. What is the probability that the household has only a cell phone or has high-speed Internet?

This probability is equal to the sum of the probability of having only a cell phone and the probability of having high-speed internet, less the probability of having both (to avoid counting this household twice).

P(C\,orI\,)=P(C)+P(I)-P(C)*P(I|C)=0.25+0.65-(0.25*0.8)=0.25+0.62-0.20=0.67

c. What is the probability that the household has only a cell phone and does not have high-speed Internet?

This is equal to the probability of not having high-speed internet given that it has a cell phone (complementaty of the proability of Point (a)) multiplied by the probability of having a cell phone.

P(C\&\bar I)=P(\bar I|C)*P(C)=(1-P(\I|C))*P(C)=(1-0.8)*0.25 = 0.2*0.25 = 0.05

d. What is the probability that the household does not have just a cell phone and does not have high-speed Internet?

This probability is complementary of the one calculated in Point (c).

P(\bar C \,or\, \bar I)=1-P(C\, or\,I)=1-0.67=0.33

e. What is the probability that the household does not have just a cell phone and does have high-speed Internet?

This is equal to the probability of having high-speed internet less the probability it has both (cell phone and internet).

P(\bar C\&I)=P(I)-P(I|C)*P(C)=0.65-0.8*0.2=0.65-0.2=0.45

7 0
4 years ago
ANSWER FAST PLZZZZZZZZZZZZZZZZZZ!!!!!!!!!!! Explain how to use estimation to help find the product of two decimals. Give an exam
xenn [34]

Answer:

what are the decimal points

5 0
3 years ago
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