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m_a_m_a [10]
3 years ago
15

ANSWER FAST PLZZZZZZZZZZZZZZZZZZ!!!!!!!!!!! Explain how to use estimation to help find the product of two decimals. Give an exam

ple with both estimated and actual answers. (5 points)
Mathematics
2 answers:
Nana76 [90]3 years ago
8 0

Answer:

Multiply to find the product. Multiply the decimals as if they were whole numbers. Ignore the decimal point. ...

Compare your estimate with your product to verify that your answer makes sense

Step-by-step explanation:

xenn [34]3 years ago
5 0

Answer:

what are the decimal points

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Use the order of operations to find the value of the expression: 20 - 12 + 8 x 5
Nezavi [6.7K]
Here’s what I got


Have nice day

6 0
3 years ago
Factor the following expression completely: 3x^2+9x+6
ArbitrLikvidat [17]

Answer:

The answer is 3(+1)(+2)

7 0
3 years ago
Read 2 more answers
Factor p^4-81 completely showing all work.
3241004551 [841]

Answer:

Step-by-step explanation:

p^4-81=(p^2)^2-9^2=(p^2+9)(p^2-9)=(p^2-9(-1))(p+3)(p-3)\\=(p^2-9i^2)(p+3)(p-3)\\=(p+3i)(p-3i)(p+3)(p-3)

8 0
3 years ago
Meg is 6 years older than Victor. Meg's age is 2 years less than five times Victor's age. The equations below model the relation
Verdich [7]

Since no possible correct method is posted, I will suggest a couple.

Method 1: guess and check

Works well for simple problems involving integers like this one.

Victor's age must be zero or greater than one, say one.

Guess v=1, find m=v+6=7, check m=5v-2=5-2=3 no good.

we need to make v bigger

Guess v=2, find m=v+6=2+6=8, check m=5v-2=5*2-2=8 ✔

So v=2, m=8.

Method 2:

Solve the system of two equations.

since the left-hand sides is m in both equations, and since m=m, we just have to equate the right-hand sides to solve for v.

5v-2=v+6

Solve for v

5v-v = 6+2

4v=8

v=2,

so again, v=2, m=v+6=2+6=8.

6 0
3 years ago
it takes someone 15 minutes to prepare 3 1/4 cups of juice how many hours would it take to prepare 32 1/2 cups of juice​
wariber [46]

\bf \begin{array}{ccll} minutes&\stackrel{juice}{cups}\\ \cline{1-2} 15&3\frac{1}{4}\\\\ x&32\frac{1}{2} \end{array}\implies \cfrac{15}{x}=\cfrac{3\frac{1}{4}}{32\frac{1}{2}}\implies \cfrac{15}{x}=\cfrac{\frac{3\cdot 4+1}{4}}{\frac{32\cdot 2+1}{2}}\implies \cfrac{15}{x}=\cfrac{\frac{13}{4}}{\frac{65}{2}}

\bf \cfrac{15}{x}=\cfrac{~~\begin{matrix} 13 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{\underset{2}{~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{\underset{5}{~~\begin{matrix} 65 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\implies \cfrac{15}{x}=\cfrac{1}{10}\implies 150=x\leftarrow \begin{array}{llll} \textit{150 minutes or}\\\\ \textit{2 hours and a half} \end{array}

4 0
3 years ago
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