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Vinil7 [7]
3 years ago
5

Need some help with Discrete Mathmatics please help urgent?

Computers and Technology
1 answer:
bearhunter [10]3 years ago
5 0

Answer: 2, 4, 1, 5, 3

<u>Explanation:</u>

P: Arguments are not arranged in regular order like the one I am used to

Q: I cannot understand         ~Q: I can understand

R: I grumble                            ~R: I do not grumble

S: Get a headache

T: Examples are not easy

Here is the logic order of the given sentences:

2)   P

4)   P →  Q

1) ~Q → ~R

5) ~R →  S

3)   S →  T

∴)   T

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Given two 2x3 (2 rows, 3 columns) arrays of integer , x1 and x2, both already initialized , two integer variables , i and j, and
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What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules

Solution:

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x1[i][j] = num.nextInt();
   }
}// End of Array 1, x1.

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x2[i][j] = num.nextInt();
   }
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:

x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
   x1rules = true;
   system.out.print(x1rules);
}
else
{
   system.out.print(x1rules);
}//Conditional Statement
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Answer:

hey! the answer to your question is -

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