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Reptile [31]
3 years ago
6

L00000000000000000000000000000000000000000000000000000000l they b00ty tickled

Computers and Technology
2 answers:
Sidana [21]3 years ago
7 0

Answer:

same bruh

Explanation:

bonufazy [111]3 years ago
5 0
Lol yeah ;-; 7777 duh
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Artists who draw images on a computer often use a stylus in conjunction with special _________ tablets, which offer extra-sensit
hodyreva [135]

Answer:

Graphics is the correct answer to the following question.

Explanation:

The following answer is true because Graphic tablet is the device in which a person can draw graphics, images or they can also draw by their hands with use of digital pen which is use for drawing as they draw images on the paper. we can also say the graphic tablet is used for the digital art.

So, That's why the following answer is correct.

6 0
3 years ago
What is your robloz?​
ira [324]

Answer:

my Ro.b.l.o.x is cookiefunny232

Explanation:

5 0
3 years ago
in cell B5 create a formula using round function that rounds the value in cell G19 to an integer, with 0 decimal places
Kitty [74]

Answer:

=ROUND(G19, 0)

Explanation:

In Microsoft Excel you would need to click on cell B5 and then click the function bar at the top and paste the following formula

=ROUND(G19, 0)

This formula will grab whatever value is in cell G19 and round it to the nearest whole integer without any decimal places at all. This is handled by the ROUND() method which takes in two arguments, the first is the cell which has the value to be rounded, and the second argument is the number of decimal places to round to. 0 indicates no decimal places.

8 0
3 years ago
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
Hoochie [10]

Answer:

I suggest a core !3

Explanation:

Its pretty good for beginners

3 0
3 years ago
Assume a computer that has 32-bit integers. Show how each of the following values would be stored sequentially in memory, starti
finlep [7]

Answer:

Adresses                          Big endian                                    Little Endian

0x100                                  AB                                                 56

0x101                                   12                                                  34

0x102                                  34                                                  12

0x103                                  56                                                 AB

0x104                                  00                                                 76

0x105                                  2B                                                 F8

0x106                                  F8                                                 2B

0x107                                 76                                                 00

0x108                                00                                                 A1

0x109                                08                                                B0  

0x10A                                B0                                                08

0x10B                                A1                                                 00

0x10C                               00                                                  01

0x10D                               00                                                 00  

0x10E                               00                                                  00

0x10F                                01                                                   00

0x110                                FE                                                   34

0x111                                 DC                                                  12

0x112                                12                                                    DC  

0x113                                34                                                   FE

Explanation:

As, it is mentioned that all the integers have 32 bits and all the data given in the question is in Hexadecimal. In Hexadecimal each number consists of 4 bits.

Each memory location contains 1 byte = 8 bits of data. So we store 2 digits of Hexadecimal number each location from each number in given data. If any number contains less than 32 bits in binary, we will add zeros to complete the number in 32 bits.

In big endian order, data is stored from upper most bit to lower most bit in sequential order and in Little Endian order it is vise versa.

6 0
3 years ago
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