One hundred and three twenty four thousandths

Skye's two new aquariums each hold exactly 200 gallons of water. One aquarium will hold small fish and the other will hold large

Natasha_Volkova [10]

Answer=140 fish

200 gallons of water in the first aquarium.

200 gallons of water in the second aquarium.

The first will be for the small fishes.

5 small fish x fish
_____________=__________
10 gallons 200 gallons

cross multiply
10x=1000
divide both sides by 10
x=100 small fish

The first aquarium has 100 small fish.

The second aquarium holds large fish.

8 large fish x fish
____________=___________
40 gallons 200 gallons

cross multiply
40x=1600
divide both sides by 40
x=40 large fish

The second aquarium has 40 large fish.

100small fish+40 large fish=140 total fish

7 0

3 years ago

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Please answer please question

Eva8 [605]

Answer:38

Step-by-step explanation:multiple

5 0

3 years ago

The summer has ended and it’s time to drain the swimming pool. 20 minutes after pulling the plug, there is still 45 000L of wate

WITCHER [35]

Answer:

a) -900 L/min

b) 63000 L

c) v = -900t +63000

d) 7200 L

Step-by-step explanation:

a) You are given two points on the curve of volume vs. time:

(t, v) = (20, 45000) and (70, 0)

The rate of change is ...

Δv/Δt = (0 -45000)/(70 -20) = -45000/50 = -900 . . . . liters per minute

__

b) In the first 20 minutes, the change in volume was ...

(20 min)(-900 L/min) = -18000 L

So, the initial volume was ...

initial volume -18000 = 45000

initial volume = 63,000 . . . . liters

__

c) Since we have the slope and the intercept, we can write the equation in slope-intercept form:

v = -900t +63000

__

d) Put the number in the equation and do the arithmetic.

When t=62, the amount remaining is ...

v = -900(62) +63000 = -55800 +63000 = 7200

7200 L remain after 62 minutes.

6 0

3 years ago

A coin is tossed four times What is the probability of getting four heads? (1 mark) a) b) What is the probability of getting exa

BlackZzzverrR [31]

<h2>Answer:</h2>

1. A coin is tossed four times. What is the probability of getting four heads?

Each toss has a 1/2 chance of getting a head.

So the chance of getting all four heads can be calculated as :

$1/2\times1/2\times1/2\times1/2=1/16$

2. A coin is tossed four times. What is the probability of getting two heads?

Each toss can have 2 results, so 4 flips will have $2^{4}$ or 16 results.

Getting two heads means getting two tails also. So, we can get the number of times two heads come = $\frac{4!}{2!2!}$ = 6

We can write the groups like - {HHTT,HTHT,HTTH,THHT,THTH,TTHH}

So, the required probability is : 6/16 or 3/8.

3. Not getting two heads means getting 3 tails and 1 head or all tails.

Probability of having all tails = $1/2\times1/2\times1/2\times1/2=1/16$

Probability of one head(1st trial) and three tails = 1/16

Probability of one head (2nd trial) and three tails (the 1st, 3rd and 4th trials) = 1/16

Probability of one head (3rd trial) and three tails (the 1st, 2nd and 4th trials) = 1/16

Probability of one head (4th trial) and three tails (the 1st, 2nd and 3rd trials) = 1/16

So, the total probability showing only one or none head and at least three tails = $1/16+1/16+1/16+1/16+1/16=5/16$

6 0

3 years ago

Does anyone know this math problem??

Slav-nsk [51]

Answer:

7

Step-by-step explanation:

pls Mark my answer in brainlist and follow me

7 0

2 years ago

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