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3 years ago

Find the value of b here

Mathematics

1 answer:

sweet [91]3 years ago

8 0

Answer:

Step-by-step explanation:

We will start with the angle that measures 57 degrees. This angle is supplementary to the one next to it coming off the straight line. 180 - 57 = 123.

The rule for quadrilaterals is that same side angles are supplementary, so the angle next to the 123-degree angle (to the immediate left of that angle 123) is 57. THAT 57-degree angle is supplementary to angle b, so angle b = 180 - 57 which is 123. So C is your answer.

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Marizza181 [45]

I believe the answer is 56 cubic feet

4 0

2 years ago

A system of equations is shown below. y = -5x - 2 y=3x - 4 What is the solution to the system of equations?

marishachu [46]

Answer:

the answer is (x,y) (1/4 -13/4)

8 0

2 years ago

A standard deck of cards contains 52 cards. One card is selected from the deck.

Anastaziya [24]

Answer:

1) Probability of randomly selecting a diamond or club = $\frac{1}{2}$

2)Probability of randomly selecting a diamond or club or heart = $\frac{3}{4}$

3) P(selecting a five or club) = $\frac{4}{13}$

Step-by-step explanation:

Total cards in the deck = 52

Noe Let E : favorable Event

So, $P(E) = \frac{\textrm{Number of Favorable outcomes}}{\textrm{Total outcomes}}$

1 ) Probability of randomly selecting a diamond or club

Here the favorable event is picking a club or diamond

hence, favorable outcomes = Number of club and diamond

= 13 + 13 = 26

⇒P(selecting a diamond or club) = $\frac{26}{52} = \frac{1}{2}$

2) Probability of randomly selecting a diamond or club or heart

Here the favorable event is picking a diamond and club and heart.

hence, favorable outcomes = Number of clubs + diamond + heart

= 13 + 13 + 13 = 39

⇒P(selecting a diamond or club or heart) = $\frac{39}{52} = \frac{3}{4}$

3 )Probability of randomly selecting a five or club.

Here the favorable event is selecting a five or club.

hence, favorable outcomes = Number of 5 in a deck + Number of clubs

= 3 + 13 = 16

⇒P(selecting a five or club) = $\frac{16}{52} = \frac{4}{13}$

3 0

3 years ago

tickets at a particular movie theatre have different rates for adults and children. on a friday the theatre sold 4 adult tickets

maria [59]

Using elimination method. Using substitution will cause some fraction problems.

c- child tickets
a- adult tickets

4a + 7c = $83
5a + 6c = $90

multiply by -5

-20a - 35c = -$415
20a + 24c = $360

-11c= -$55
c = $5 child tickets

4a + 7(5)= $83

4a + 35 = $83

4a = $48

a= $12 adult tickets

4 0

3 years ago

PLEASE SHOW YOUR WORK

lakkis [162]

Answer:

Step-by-step explanation:

5 0

3 years ago