Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is
Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,
Putting the given values, we get
Therefore, the area of 4 walls of the room is 54 sq. metres.
Answer:
267
Step-by-step explanation:
We are given the expression: 6 (d - f) +f
The value of the expression when d= 47 and f = 3 is :
6 (47 - 3) +3 = 6×(44) + 3 = 264 + 3 = 267
=267
For this you need to multiply 1,500 by 60 (because there are 60 seconds in a minute) and then multiply that by 2 (because there are 2 minutes), wich makes the answer 180,000 meters.
Does this help?
Answer more questions on every topic you’ve been thought. Answer research questions and questions likely to come out in the exam. Dwell on what you are trying to know more that what you already know. A planner could help as well and the Good God would help you
Answer:
(3,2)
Step-by-step explanation:
