Problem 3: Let x = price of bag of pretzels Let y = price of box of granola bars
We have Lesley's purchase: 4x+2y=13.50
And Landon's: 1x+5y=17.55
We can use the elimination method. Let's negate Landon's purchase by multiplying by -1. -1x-5y=-17.55
We add this four times to Lesley's purchase to eliminate the x variable.
2y-20y=13.50-70.2
-18y=-56.7
y = $3.15 = Price of box of granola bars
Plug back into Landon's purchase to solve for pretzels.
x+5*3.15=17.55
x+15.75=17.55
x = $1.80 = price of bag of pretzels
Problem 4.
Let w = number of wood bats sold
Let m = number of metal bats sold
From sales information we have: w + m = 23
24w+30m=606
Substitution works well here. Solve for w in the first equation, w = 23 - m, and plug this into the second.
24*(23-m)+30m=606
552-24m+30m=606
6m=54
m=9 = number of metal bats sold
Therefore since w = 23-m, w = 23-9 = 14. 14 wooden bats were sold.
Answer:
So to maximize profit 24 downhill and 20 cross country shouldbe produced
Step-by-step explanation:
Let X be the number of downhill skis and Y the number of cross country skis.
Time required for manufacturing and finishing each ski are: manufacturing time per ski, downhill 2.5 hours, cross country 1.5 hours
Finishing time per ski: downhill 0.5 hours, cross country 1.5 hours.
Total manufacturing time taken = (2.5) x+ (1.5+) y = 2.5x+1.5y≤90
total finishing time taken = 0.5x+1.5 y≤42
Profit function
Z = 50x+50y
Objective is to maximize Z
Solving the two equations we get intersecting point is
(x,y) = (24,20)
In the feasible region corner points are (0.28) (36,0)
Profit for these points are
i) 2200 for (24,20)
ii) 1400 for (0,28)
iii) 1800 for (36,0)
So to maximize profit 24 downhill and 20 cross country shouldbe produced.
Answer:
b^4 / a
Step-by-step explanation:
I have attached the explanation above. hopefully this will help
A. Because the paint depends of the cubes
(I’m pretty sure)
Answer:
87 in³
Step-by-step explanation:
that is the solution above