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FrozenT [24]
3 years ago
11

For each geometric sequence, write a recusive rule by finding the commom ratio by calculating the ration of consecutive terms. W

rite an exlicit rule for the sequence by writing each term as the product of the first tern and a power of the common ratio.
n- 1, 2, 3, 4, 5
An- 2, 6, 18, 54, 162
Mathematics
1 answer:
Inessa05 [86]3 years ago
3 0

Answer:

a_n=2.(3)^{n-1}

Step-by-step explanation:

Given sequence is:

2,6,18,54,162

So the common ratio can be found by dividing the second term by first term:

r = 6/2 = 3

The standard formula for geometric sequence is:

a_n=a_1r^{n-1}

Putting the value of r

a_n=2.(3)^{n-1}

So,

a_1=2.(3)^{1-1} => 2.3^0 = 2*1 = 2\\a_2=2.(3)^{2-1} => 2.3^1 = 2*3 = 6\\a_3=2.(3)^{3-1} => 2.3^2 = 2*9 = 18\\a_4=2.(3)^{4-1} => 2.3^3 = 2*27 = 54\\a_5=2.(3)^{5-1} => 2.3^4 = 2*81 = 162

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<img src="https://tex.z-dn.net/?f=f%20-%20354%20%3D%201221" id="TexFormula1" title="f - 354 = 1221" alt="f - 354 = 1221" align="
alukav5142 [94]

f-354=1221           <em>add 354 to both sides</em>

f+354-354=1221+354\\\\\boxed{f=1,575}\to\boxed{D.}

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