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Nadusha1986 [10]
3 years ago
8

entry that has the address of 192.168.101.0 and the wildcard mask of 0.0.0.255. What is the range of IPv4 addresses that will be

affected by this ACL?
Computers and Technology
1 answer:
svp [43]3 years ago
6 0

Answer:

192.168.101.0 through 192.168.101.255 is the correct answer.

Explanation:

The following answer is correct because the address of the ACL entry is 192.168.101.0 and 0.0.0.255 is the wildcard mask then, the range of the IPv4 addresses is 192.168.101.0 through 192.168.101.255 that affected by the ACL.

ACL is referred as the access control list that acts as the firewall which secures the VPC network of the user.

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Start with the following Python code. alphabet = "abcdefghijklmnopqrstuvwxyz" test_dups = ["zzz","dog","bookkeeper","subdermatog
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#Part 1 Write a function called has_duplicates that takes a string parameter and returns True if the string has any repeated characters. Otherwise, it should return False.

def has_duplicates(stringP):

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   for key,value in dic.items():

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# Implement has_duplicates by creating a histogram using the histogram function above. Write a loop over the strings in the provided test_dups list.

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#Part 2 Write a function called missing_letters that takes a string parameter and returns a new string with all the letters of the alphabet that are not in the argument string.

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