The answer is C.
The man’s genotype must be AB. The woman’s genotype can be either BB or BO as both correspond to a blood type (which is a phenotype) of B.
Each parent passes on one allele. The man can contribute A or B and the woman can contribute B or O.
The possible genotype combinations are therefore AB, AO, BB, and BO. These correspond to the phenotypes AB, A, B, and B.
b hfdfcvyghfxdsgyuihgfhfdrsfghjgfdsafghjkhgftdrsfghjkhgf hjkhgfdg
Telophase 2 is the final step of meiosis 2 in which homologous chromosomes reach the opposite poles and four haploid cells are formed.
Explanation:
The telophase 2 ends up in four haploid (n=2) cells. It is in this phase the genetic material of the parent cell is divided into 2 daughter cells. The events taking place are nuclear membrane reappears (karyokinesis has taken place by now), spindle fibres and astral rays disappear, chromosomes decondensed to become chromatids (thin fibres), constriction on equatorial plate consequently four daughter cells formed.
Answer:
here is the answer :))))))))))
Explanation:
bc y not
D is the correct answer ur welcome
