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Inga [223]
3 years ago
11

A cone has a radius of five feet and a height of 18 feet. If the radius of the cone is tripled but the volume but the volume rem

ains unchanged, what will be the new height of the cone
Mathematics
1 answer:
olasank [31]3 years ago
4 0
Volume of a cone is 1/3 of the area of the base times the height
 v=(1/3)pi*5*5*18=(1/3)pi815*15*h
h=2

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Do both of them please
Neko [114]

Answer:

$ 333

Step-by-step explanation:

a) 33 + m*1 = 33 + m

b) m = 300 miles

33 + m = 33 + 300

           = $ 333

8 0
3 years ago
O graph the equation 2x + 5y = 10, Zeplyn draws a line through the points (5, 0) and (0, 2). What is the slope of the line repre
JulijaS [17]
2x + 5y = 10
Change to y = mx + b
subtract 2x from both sides
5y = -2x + 10
divide both sides by 5
y = -2/5x + 2
slope = -2/5
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6 0
3 years ago
Read 2 more answers
Solve the equation 3b=42
SIZIF [17.4K]

Answer:

b=14

Step-by-step explanation:

42 divided by 3 is 14

5 0
3 years ago
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En la preparación de un perfume se cuenta con dos tipos de esencia base: 1600 ml de una y 1680 ml de otra. Se quiere envasarlas,
Lostsunrise [7]

Answer:

33,600 frascos

Step-by-step explanation:

Resolvemos esta pregunta utilizando el método mínimo común múltiple

Encuentre y enumere los múltiplos de 1600 y 1680 hasta encontrar el primer múltiplo común. Este es el mínimo común múltiplo.

Múltiplos de 1600:

1600, 3200, 4800, 6400, 8000, 9600, 11200, 12800, 14400, 16000, 17600, 19200, 20800, 22400, 24000, 25600, 27200, 28800, 30400, 32000, 33600, 35200, 36800

Múltiplos de 1680:

1680, 3360, 5040, 6720, 8400, 10080, 11760, 13440, 15120, 16800, 18480, 20160, 21840, 23520, 25200, 26880, 28560, 30240, 31920, 33600, 35280, 36960

Por lo tanto,

LCM (1600, 1680) = 33,600

La menor cantidad de frascos necesarios es 33,600 frascos.

4 0
3 years ago
Any help would be great
nadya68 [22]

Answer:

15

Step-by-step explanation:

38=10+13+c

c=38-10-13=15

Hope this helps!

8 0
3 years ago
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