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PSYCHO15rus [73]
3 years ago
13

Create a model to show 2 × 5.

Mathematics
1 answer:
Sliva [168]3 years ago
5 0

Answer:

The model is shown in the attached picture. The solution is 10.

Step-by-step explanation:

There are two way of showing a model for 2×5

  1. The tape diagram has 2 equal-sized parts of 5
  2. The tape diagram has 5 equal-sized parts of 2

Both models give the same solution:

  1. 5+5=10
  2. 2+2+2+2+2=10

In the attached picture we can show two types of diagram.

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3 x A = 30 + 30<br><br> it’s a 3rd grade problem but don’t know the answer
xenn [34]

Answer: A=20

Step-by-step explanation:

3×A=30+30............eqn 1

3A=60

A=60/3

A=20

Substitute A=20 into equation 1

3x20= 30+30

8 0
3 years ago
A computer programming team has 13 members. a. How many ways can a group of seven be chosen to work on a project? b. Suppose sev
Julli [10]

Answer:

1716 ;

700 ;

1715 ;

658 ;

1254 ;

792

Step-by-step explanation:

Given that :

Number of members (n) = 13

a. How many ways can a group of seven be chosen to work on a project?

13C7:

Recall :

nCr = n! ÷ (n-r)! r!

13C7 = 13! ÷ (13 - 7)!7!

= 13! ÷ 6! 7!

(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)

1235520 / 720

= 1716

b. Suppose seven team members are women and six are men.

Men = 6 ; women = 7

(i) How many groups of seven can be chosen that contain four women and three men?

(7C4) * (6C3)

Using calculator :

7C4 = 35

6C3 = 20

(35 * 20) = 700

(ii) How many groups of seven can be chosen that contain at least one man?

13C7 - 7C7

7C7 = only women

13C7 = 1716

7C7 = 1

1716 - 1 = 1715

(iii) How many groups of seven can be chosen that contain at most three women?

(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)

Using calculator :

(15 * 35) + (6 * 21) + (1 * 7)

525 + 126 + 7

= 658

c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?

(First in second out) + (second in first out) + (both out)

13 - 2 = 11

11C6 + 11C6 + 11C7

Using calculator :

462 + 462 + 330

= 1254

d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?

Number of ways with both in the group = 11C5

Number of ways with both out of the group = 11C7

11C5 + 11C7

462 + 330

= 792

8 0
2 years ago
The ratio of men to women working for a company is to 8 to 5 . If there are employees total 208 , how many women work for the co
Vikki [24]

Answer:

130

ratio of woman to man is : 5/8

5/8×208=130

8 0
2 years ago
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Insert parentheses to make the statement true <br> 21-8-6=7
Advocard [28]

(21-8)-6=7

and that's it

5 0
3 years ago
Kyle ran 2/3 mi on Monday,1 1/6 mi on Tuesday, and 7/12 mi on Wednesday.
BartSMP [9]

you would change the denominators to the least common multiple, in this case, 12. then you would change the fractions to 8/12, 14/12, and 7/12. you would add those, and get 29/12. divide 29 by 12, and get 2. add the rest to get 2 5/12.
7 0
3 years ago
Read 2 more answers
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