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NNADVOKAT [17]
3 years ago
5

??????????????????????????????????

Mathematics
2 answers:
beks73 [17]3 years ago
8 0

Answer:

duh its  27a^{3}b2

yanalaym [24]3 years ago
6 0

Answer:

It is b^6

Step-by-step explanation:

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Suppose a basketball player has made 184 out of 329 free throws. If the player make the next two free throws, I will pay you $24
Marta_Voda [28]
Given that the player made 184 out of 329 throws, the probability of making the next throw will be:
P(x)=[Number of shots made]/[Total number of throws]
=184/329
=0.559
Thus the expected value of proposition will be:
0.599*24+0.559*12
=20.134
8 0
3 years ago
If the lengths of two sides of a triangle are 5 and 9, respectively, which of the following could be the length of the third sid
slamgirl [31]

There are two answers:

B) 5

C) 8

==============================================

Explanation:

If we had a triangle with sides a, b and c, then we can say

b-a < c < b+a

where b is larger than 'a'. This is the triangle inequality theorem

In this case, a = 5 and b = 9 so,

b-a < c < b+a

9-5 < c < 9+5

4 < c < 14

Telling us that c is some number between 4 and 14, not including either endpoint. If c is a whole number, then c could be any value from this set: {5,6,7,8,9,10,11,12,13}

We see that the numbers 5 and 8 are in this set. The values 3 and 15 are not in the set.

3 0
3 years ago
Problem of the Week
Ierofanga [76]

Answer:

CD is 6 cm and DE is 4 cm.

Step-by-step explanation:

Well it‘s the correct answer and I got it right so good luck out there bois!

6 0
3 years ago
Pls help friend memeeeememmeme
abruzzese [7]
D, volume = widthxheightxlength
8 0
3 years ago
Read 2 more answers
How many different four-digit numbers can be made using the digits 1,2,3,4,5,6 if no digit can be used more than once?
igomit [66]

Answer:

360

Step-by-step explanation:

The given digits are 1,2,3,4,5,6.

So, total number of digits = 6.

We need to find the number of different ways to form four-digit numbers using the digits, without repetition.

Total ways for first place = 6

After selecting 1 digit the number of remaining digits is 5. So,

Total ways for second place = 5

Similarly,

Total ways for third place = 4

Total ways for forth place = 3

Total number of ways = 6\times 5\times 4\times 3=360

Therefore, 360 four digit numbers are possible.

5 0
3 years ago
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